Carlos invested part of $3,000 in a 10% certificate account and the rest in a 6% passbook account. The total annual interest fro
1 answer:
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The Venn Diagram that represents the problem is shown below
P(E|F) and P(F|E) are the conditional probability.
P(E|F) is given by P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is given by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1
P(E|F) and P(F|E) are the conditional probability.
P(E|F) is given by P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is given by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1
The data has been properly arranged in tabular form and is shown below in the image.
First we need to find the mean and median of scores of both students.
1) For Amo:
Mean =
Median = Middle Value when data is arranged in ascending order = 90
2) For Javier:
Mean =
Median = Middle Value when data is arranged in ascending order = 92
For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.
First we need to find the mean and median of scores of both students.
1) For Amo:
Mean =
Median = Middle Value when data is arranged in ascending order = 90
2) For Javier:
Mean =
Median = Middle Value when data is arranged in ascending order = 92
For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.
Answer:
a) 20 ways
b) 10 ways
Step-by-step explanation:
When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.
Part a)
We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2
General formula of permutations of n objects taken r at time is:
Using the value of n=5 and r=2, we get:
Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.
Part b)
Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.
The general formula of combinations of n objects taken r at a time is:
Using the value of n=5 and r=2, we get:
Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice does not matters.