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1 year ago

What statement is an example of addition property of equality

Mathematics

1 answer:

Flura [38]1 year ago

3 0

Answer:

The formal name for the property of equality that allows one to add the same quantity to both sides of an equation. This is one of the most commonly used properties for solving equations.

The formula tells us that if a = b, then a + c = b + c. The letters a and b stand for two separate numbers, our two twins, and the letter c stands for what we give to each twin to keep them matching. So, for example, if we add 1 to the left side of the equation, we must also add 1 to the right side of the equation. By doing this, we keep the equation, the twins, the same.

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Answer:

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1 year ago

In a triangle ABC,AB=9 and BC =12 which of the following Cannot be the length of AC.

galben [10]

Step-by-step explanation:

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5 0

2 years ago

Given the function f(x) = 3x, find the value of f−1(81).

Shalnov [3]

Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
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4 0

1 year ago

How does the graph of mc024-1.jpg compare to the graph of the parent function mc024-2.jpg?

ss7ja [257]

The question is as following:
How does the graph of g(x)=1/x-5+2 compare to the graph of the parent function f(x)=1/x ?

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Solution :
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The given function ⇒ $g(x) = \frac{1}{x-5} +2$

The parent function of the given function ⇒ $f(x)= \frac{1}{x}$

By graphing both of the equations as shown in the attached figure.
So, we can conclude the following
g(x) is shifted 5 units right and 2 units up from f(x).


So, the correct answer is option 2

6 0

1 year ago

Read 2 more answers

You plan to accumulate 100,000 at the end of 42 years by making the follow-

Mariana [72]

Answer:

Y = 479.17

Step-by-step explanation:

At the end of year 14, the balance from the deposits of X can be found using the annuity due formula:

A = P(1+r/n)((1 +r/n)^(nt) -1)/(r/n)

where P is the periodic payment, n is the number of payments and compoundings per year, t is the number of years, and r is the annual interest rate.

A = X(1.07)(1.07^14 -1)/0.07 ≈ 24.129022X

This accumulated amount continues to earn interest for the next 28 years, so will further be multiplied by 1.07^28. Then the final balance due to deposits of X will be ...

Ax = (24.129022X)(1.07^28) = 160.429967X

The same annuity due formula can be used for the deposits of Y for the last 10 years of the interval:

Ay = Y(1.07)(1.07^10 -1)/.07 = 14.783599Y

Now we can write the two equations in the two unknowns:

Ax +Ay = 100,000

X - Y = 100

From the latter, we have ...

X = Y +100

So the first equation becomes ...

160.429967(Y +100) +14.783599Y = 100000

175.213566Y +16,043.00 = 100,000

Y = (100,000 -16,043)/175.213566 ≈ 479.17

Y is 479.17

7 0

1 year ago