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svp [43]
1 year ago
15

What statement is an example of addition property of equality

Mathematics
1 answer:
Flura [38]1 year ago
3 0

Answer:

The formal name for the property of equality that allows one to add the same quantity to both sides of an equation. This is one of the most commonly used properties for solving equations.

The formula tells us that if a = b, then a + c = b + c. The letters a and b stand for two separate numbers, our two twins, and the letter c stands for what we give to each twin to keep them matching. So, for example, if we add 1 to the left side of the equation, we must also add 1 to the right side of the equation. By doing this, we keep the equation, the twins, the same.

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Explain whether 13t−3t is equivalent to 3t−13t. Support your answer by evaluating the expressions for t=2.
djverab [1.8K]

Answer:

  • Not equivalent

Step-by-step explanation:

  • 13t - 3t = (13 - 3)t = 10t
  • 3t - 13t = (3 - 13)t = -10t
  • 10t ≠ -10t

They are not equivalent

<u>When t = 2</u>

  • 13t - 3t = 13*2 - 3*2 = 26 - 6 = 20
  • 3t - 13t = 3*2 - 13*2 = 6 - 26 = -20
6 0
1 year ago
Read 2 more answers
A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at r
laila [671]

Answer:

Probability that Adam and Ella will be selected:

\displaystyle \frac{1}{10}=0.1

Step-by-step explanation:

Probabilities

The probability of a random event E to occur is a real number between 0 and 1, both inclusive, where 0 indicates an impossible event and 1 a sure event. There are many techniques to compute probabilities depending on the particular situation and distribution.

This question will be solved by simple calculations and logic, given its simplicity. We know the middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two of them are going to be selected at random to participate in the county chess tournament. We can calculate the number of different ways it can be done without any restriction. It's called the sample space.

The sample space of this event is the combination of 5 members regardless of their position. If {a,b,c,d,e} are the five members, then the possible combinations are {ab,ac,ad,ae,bc,bd,be,cd,ce,de}. Notice that there are only 10 possibilities because the combination ab is the same as ba since it's the same team for the tournament.

We can see there is only one combination of two specific letters out of 10. If a=Adam and e=Ella, only one combination is ae, the other 9 don't include both members, so the probability is

\displaystyle P(ae)=\frac{1}{10}=0.1

3 0
1 year ago
Computer upgrades have a nominal time of 80 minutes. samples of five observations each have been taken, and the results are as l
Goshia [24]
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is 

for the mean chart
uclim= x+A2xR
where x = sum(of the value)  / number of each value
and for 
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin

in the case of the sample 1: S1
the data are: 
79.2    78.8   80.0   78.4   81.0

the mean is   x1 = (</span>79.2  +  78.8  +  80.0  + 78.4  + 81.0)  / 5=  79.48
<span>its range is    R 1= 81.0 -78.4 = 2.6

we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14  ,  R2=2.3
</span>S3: x3= 80.14  ,  R3=1.2
S4: x4= 79.60  ,  R4=1.7
S5: x5= 80.02  ,  R5=2.0
S6: x6=80.38   ,  R6=1.4
<span>
therefore the average value is   X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95  and lclim is always equal to 0, because D3=0

we can say that the process is not in control.
       




</span>
3 0
2 years ago
Mario has a 500 page novel which he is required to read over summer break for his upcoming language arts class if Mario read 24
KonstantinChe [14]

Answer:

p(d) = 24p + 500d

Step-by-step explanation:

p(d) = 24p + 500d

hopefully this helps ;)

Can you answer my question pleaseeee?

3 0
2 years ago
Choose the most accurate statement based on the graph shown.
Eddi Din [679]
The most accurate would be the second statement: <span>The graph is misleading because it uses 3-dimensional bars.

The vertical range is just enough. It only appears small because the bars are in 3D. It should have been in 2D so that we could directly trace it to how much frequency each category is. Even the axes are in 3D also.</span>
4 0
1 year ago
Read 2 more answers
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