All categories

1 year ago

What statement is an example of addition property of equality

Mathematics

1 answer:

Flura [38]1 year ago

3 0

Answer:

The formal name for the property of equality that allows one to add the same quantity to both sides of an equation. This is one of the most commonly used properties for solving equations.

The formula tells us that if a = b, then a + c = b + c. The letters a and b stand for two separate numbers, our two twins, and the letter c stands for what we give to each twin to keep them matching. So, for example, if we add 1 to the left side of the equation, we must also add 1 to the right side of the equation. By doing this, we keep the equation, the twins, the same.

You might be interested in

A student theater charges $9.50 per ticket. The theater has already sold 70 tickets. Write and solve an inequality that represen

Genrish500 [490]

9.50 times 70 is greater or less than 1000

8 0

1 year ago

Jared is placing chairs around of rectangular stage. The stage is 10 feet long and 22 feet wide. He wants to put a chair at each

marishachu [46]

Hi there, I believe the answer is 20. Because, each corner is 4 chairs plus every two feet, equals 20. Hope this helps!

3 0

2 years ago

Read 2 more answers

Mrs. Adams bought cans of pears and cans of mixed fruit.

weeeeeb [17]

Answer: 5 Cans

Step-by-step explanation:

4 0

1 year ago

Which binomial is a factor of 49x2 + 84xy + 36y2?

statuscvo [17]

Answer:

A. 7x + 6y

Step-by-step explanation:

49x² + 84xy + 36y²

Factoring the perfect square:

(7x + 6y)²

7x + 6y is a factor.

7 0

1 year ago

Two friends compete with each other and five other, equally good, violinists for first and second chair in an orchestra, in a bl

Darina [25.2K]

Answer: 0.0476

Step-by-step explanation:

Given : Two friends and 5 other people compete with each other for first and second chair in an orchestra.

Total people in this competition= 2+5=7

By permutation , Number of ways to arrange 7 people= 7!

Also, number of ways for two friends end up as first and second chair together= 2 × 5! [ 2 ways to arrange friends on first and second chair and 5! ways to arrange others]

I.e. Required probability = $\dfrac{2\times5!}{7!}$

$=\dfrac{2!\times5!}{7\times6\times5!}\\\\=\dfrac{1}{7\times3}\\\\=\dfrac{1}{21}\\\\=0.0476$

Hence, the probability that the two friends end up as first and second chair together = 0.0476

4 0

2 years ago