3.7 ÷ 1.1 = ? Round to the nearest hundredth. A. 0.297 B. 3.36 C. 4.07 D. 4.8

Nick is 30 years less than 3 times Rays age. If the sum of their ages is 74,how old are each of the men? Solve and write an equa

zaharov [31]

Nick = n
Ray = r

n=3r-30
n+r=74

3r-30+r=74
4r-30=74
4r=104
r=26
n=26*3-30
n=78-30
n=48
Nick is 48 years old and Ray is 26 years old
Hope this helps.

5 0

2 years ago

Mary deposits $550 in a savings account at 3% simple annual interest. The

kupik [55]

Answer:

Domain: $t \geq 0$

Range: $v \geq 550$

Step-by-step explanation:

Given

$v = 550 + 16.5t$

Required

Determine the domain and the range

Solving for domain:

From the question, we understand that t represent years.

Because years can't be negative;

Then, we can conclude that the domain, t is:

$t \geq 0$

Solving for Range:

We solved domain to be $t \geq 0$

This implies that the minimum value of t is $t = 0$ and the maximum is infinity

Substitute 0 for t in $v = 550 + 16.5t$

$v = 550 + 16.5(0)$

$v = 550 + 0$

$v = 550$

Hence;

The range is $v \geq 550$

6 0

2 years ago

A company mixes pecans, cashews, peanuts, and walnuts to make a batch of mixed nuts. About 15.4% of the mixed nuts in a batch ar

Elan Coil [88]

Answer:

500 lb

Step-by-step explanation:

You have to make a proportion:

$\frac{part}{whole} = \frac{percent}{100}$

77 lb is part of the whole weight ( which we don't know) so 77 will go on top

The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

$\frac{77}{x} = \frac{15.4}{100}$

Then you cross multiply giving you: 7700 = 15.4x

then you divide 15.4 to both sides to isolate x which will give you 500

4 0

2 years ago

20% of the tickets sold at a water park were adult tickets. If the park sold 55 tickets in all,how many did it sell?

djyliett [7]

Answer:

11 adult tickets

Step-by-step explanation:

I guess you want the number of adult tickets sold.

That is 20% of 55

= 0.20*55

= 11 (answer)

8 0

2 years ago

Read 2 more answers

A brewery produces cans of beer that are supposed to contain exactly 12 ounces. But owing to the inevitable variation in the fil

MArishka [77]

Answer:

$T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)$

$P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solutio to the problem

Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:

$X \sim N(12,0.3)$

Where $\mu=12$ and $\sigma=0.3$

For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.

The definition of sample mean is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n} = \frac{T}{n}$