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2 years ago

What is the value of x which proves that the runways are parallel? What is the measure of the larger angle?

Mathematics

2 answers:

Semenov [28]2 years ago

6 0

The answer is C) x = 25; 107 degrees

Temka [501]2 years ago

3 0

Answer:

The correct option is C.

Step-by-step explanation:

if a transversal line intersect two parallel lines then the sum of two consecutive exterior angles is 180 degrees.

The two consecutive exterior angles are 3x+32 and x+48.

$3x+32+x+48=180$

$4x+80=180$

$4x=180-80$

$4x=100$

$x=25$

The value of x is 25.

The measure of two consecutive exterior angles are

$3x+32=3(25)+32=107$

$x+48=25+48=73$

The measure of the larger angle is 107 degrees.

Therefore the correct option is C.

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Van is 75% than kieth .if van's heightt increasess by 40% while kieth's increases only by 25%, by what percent is van taller tha

Lilit [14]

I think there is a lack of information with regards to the question posted above. This may be the complete question:

Van is 75% taller than Keith. If Van's height increases by 40% while Kieth's increases only by 25%, by what percent is Van taller than Kieth now?

We put Van at 175 and Kieth at 100 since Van is 75% taller than Keith.
When Kieth's height increased at 25%, he is now 125
When Van's height increased at 40%, he is now 245

245-125=120 and

120/125= .96 = 96%

The answer is 96%. I hope this helps.

3 0

2 years ago

g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t

Evgesh-ka [11]

Answer:

Z-score 1.96

Margin of error d= 0.04323

Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

n= 500

The parameter of interest is the proportion of people that opposes it.

The estimated proportion is p'= 300/500= 0.6

To estimate the population proportion per Confidence interval you have to approximate the distribution of the sample proportion p' to normal:

p'≈N(p;p(1-p)1/n)

The mean of this distribution is p and the variance is p*(1-p)*1/n

To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

Where " $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$ " represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is $Z_{0.975}= 1.965$

The estimated standard error is already calculated: $\sqrt{\frac{p'(1-p')}{n} } = 0.022$

The margin of error (d) is then:

d= $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$ = 1.965 * 0.022

d= 0.04323

I hope it helps!

7 0

1 year ago

It takes Wayne 1/10 hours to walk a 1/6 mile park loop. What is Wayne's unit rate, in miles per hour

olchik [2.2K]

To solve this problem, we should set up a proportion, letting x represent our unknown number of miles that Wayne walks in one hour.

1/6 mile / 1/10 hours = x miles / 1 hour

Now we use cross-products or the multiplication of the numerator of one fraction times the denominator of the other fraction, setting these two numbers equal. The resulting equation is:

1/6 = 1/10x

Finally, we must divide both sides by 1/10 to cancel it out on the right side of the equation and get the variable x alone.

x = 5/3 or 1 2/3

Therefore, Wayne walks 1 2/3 miles per hour.

5 0

2 years ago

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It should be B or the second one

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2 years ago

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The box-and-whisker plot below shows the age distribution of people at a family reunion. A box-and-whisker plot is shown. The nu

Setler79 [48]

Answer:

The answer is C