Question

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).
Y=-0.02x^2+0.8x+3


What will the height of the ball be at a distance of 10 feet?


A. 6
B. 7
C. 8
D. 9

Answer 1

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = $-0.02x^{2} +0.8x+3$

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = $-0.02x^{2} +0.8x+3$

Y(x) = $-0.02(10)^{2} +0.8(10)+3$

Y(x) = $-0.02(100)} +8+3$

Y(x) = $-2 +8+3$

Y(x) = $9$

Therefore, Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D.  9 ft is correct