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kow [346]
2 years ago
14

If f(x) = 5x + 40, what is f(x) when x = –5? a.–9 b.–8 c.7 d.15

Mathematics
2 answers:
Helen [10]2 years ago
5 0

Answer:

f(x)=15 d.

Step-by-step explanation:

To begin solving the equation you need to substitute -5 in for x.

The equation would then read f(x)=5(-5)+40

Then you need to simplify 5 times -5 is -25

the equation would be f(x)=-25+40

Then you would simplify and you will get f(x)=15

defon2 years ago
3 0

Just plug the number

_5(5)+40=-25+40

=15

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Sheri’s cab fare was $32, with a 20% gratuity and no taxes. Sheri wrote a check to the cab driver for $40.
stira [4]

Yes, $40 is a reasonable amount to pay for the cab fare.

<em><u>Explanation</u></em>

Sheri’s cab fare was $32 and the percentage of gratuity is 20%

So, the amount of gratuity will be: \$32* 20\% = \$32*0.20= \$6.40

Thus, <u>the fare of the cab including the gratuity</u> will be:  \$32+\$6.40 = \$38.40

As Sheri wrote a check to the cab driver for $40 , it means she paying ($40 - $38.40) or <u>$1.60 more to the cab driver</u>. So, the $40 check is a reasonable amount to pay for the cab fare.

5 0
2 years ago
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Juan put three square tiles with sides 8 centimeters, 10 centimeters, and x centimeters together so that they form a right trian
Elan Coil [88]
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to x^{2}.
A = x^{2} ---> equation (1)
By using pythagoras rule which states that the x^{2} = hyp^2 - opposite^2---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
x^{2} = 10^{2} - 8^{2} substitute this value in equation (1) then
A = x^{2} = 10^{2} -8^{2}
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6 0
1 year ago
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Zoe the goat is tied by a rope to one corner of a 15 by 25 meter rectangular barn in the middle of a large, grassy field. Over w
atroni [7]

Answer: 78.55\ m^2

Step-by-step explanation:

Given

The goat is tied by a rope to one corner of a rectangular field with length of rope 10 m.

Zoe can graze in an area equal to quadrant of circle with radius 10 m

Area of grazing is

\Rightarrow \dfrac{1}{4}\times \pi r^2\\\\\Rightarrow \dfrac{\pi r^2}{4}\\\\\Rightarrow \dfrac{\pi \times 10^2}{4}=78.55\ m^2

6 0
1 year ago
Write standard form<br> 5+0.5+0.03+0.006
zmey [24]

Answer:

5.5360

Step-by-step explanation:

I added

5+0.5= 5.5

5.5+0.03=5.53

5.53+0.006=

5.5360

3 0
1 year ago
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Andrea has a yard shaped like parallelogram ABCD. The garden area, parallelogram EFGB, has an area of 105 ft2004-05-02-04-00_fil
Lynna [10]

The area of a parallelogram is simply calculated using the formula:

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Where,

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2 years ago
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