Answer:
Step-by-step explanation:
Sample size = 95
X=cash carried by the persons
x bar = 8.00
s = sample std dev = 2.50
Std error = 
Hence Z score would be
-0.00
b) 
c) 95% conf interval margin of error = ±
=±0.54782
Confi interval = (8-0.5027, 8+0.5027)
= (7.4923, 8.5027)
C)If conf level increases, then width of interval would increase since critical value would increase.
If sample size increases std error would decrease and hence margin of error.
So interval would decrease.
The whole second is the first number to the left of the decimal (_.), so : 35.78=36 because 7>5. 39.51=40 because 5=5. 40-36=4. Bailey won the race by about 4 seconds. Hoped I helped!
<h2>Answer</h2>
0.43
<h2>Explanation</h2>
Remember that 
Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so 
. Now, the sum of all frequencies will be the sum of all the 10th graders, so 
. Let's replace the values:
And rounded to the nearest hundredth:
