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Vinil7 [7]
1 year ago
6

Which is the solution of the quadratic equation (4y – 3)2 = 72?

Mathematics
2 answers:
Ymorist [56]1 year ago
9 0

Answer:

y = \frac{3+6\sqrt{2}}{4}\text{ and } y = \frac{3-6\sqrt{2}}{4}

Step-by-step explanation:

Given quadratic equation,

(4y-3)^2=72

\implies 4y - 3 = \pm \sqrt{72}   ( Taking root on both sides )

4y=3 \pm 6\sqrt{2}     ( Additive property of equality ),

y = \frac{3 \pm 6\sqrt{2}}{4}   ( Division property of equality )

\implies y = \frac{3+6\sqrt{2}}{4}\text{ or }y =\frac{3-6\sqrt{2}}{4}

Hence, the solution of the given equation is,

\implies y = \frac{3+6\sqrt{2}}{4}\text{ and }y =\frac{3-6\sqrt{2}}{4}

e-lub [12.9K]1 year ago
6 0

Answer:

y = 9.75

Step-by-step explanation:

(4y - 3)2 = 72

Opening the brackets;

8y - 6 = 72

8y = 72 + 6 = 78

y = 78 ÷ 8 = 9.75

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What is the constant of variation for the quadratic variation? 0.1y = 3x2
svet-max [94.6K]

Answer:

The constant of variation for the given quadratic equation is, 30

Step-by-step explanation:

One of the form of a quadratic equation is written as:

y = kx^2     ....[1]

where k is the coefficient and for this case the constant of variation.

In order to obtain the answer for the given equation, we write the given equation to the form above.

0.1y=3x^2  or

y=(\frac{3}{0.1})x^2 or

y=30x^2

Comparing this equation with equation [1], to get the value of k;

k=30.

therefore, the  constant of variation is, 30.

6 0
2 years ago
Consider the following sample of observations on coating thickness for low-viscosity paint.
Julli [10]

Answer:

a) \bar X = \frac{\sum_{i=1}^n X_i}{n}

And for this case if we use this formula we got:

\bar x = 1.3538

b) Since we have n =16 values for the sample the median can be calculated as the average between position 8th anf 9th and we got:

Median = \frac{1.31+1.46}{2}= 1.385

c) P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=1.3538 +1.28*0.3505=1.8024

So the value of height that separates the bottom 90% of data from the top 10% is 1.8024.  

d) Median= \frac{x_{8} +x_{9}}{2}

The variance for this estimator is given by:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} Var(X_{8} +X_{9})

We can assume the obervations independent so then we have:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} (2\sigma^2) = \frac{\sigma^2}{2}

And replacing we got:

Var(\frac{x_{8} +x_{9}}{2})= \frac{0.3105^2}{2}= 0.0482

And the standard error would be given by:

Sd(\frac{x_{8} +x_{9}}{2})= \sqrt{0.0482}=0.2196

Step-by-step explanation:

Data given:

0.86 0.88 0.88 1.07 1.09 1.17 1.29 1.31  1.46 1.49 1.59 1.62 1.65 1.71 1.76 1.83

Part a

We can calculate the mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And for this case if we use this formula we got:

\bar x = 1.3538

Part b

For this case in order to calculate the median we need to put the data on increasing way like this:

0.86 0.88 0.88 1.07 1.09 1.17 1.29 1.31 1.46 1.49  1.59 1.62 1.65 1.71 1.76 1.83

Since we have n =16 values for the sample the median can be calculated as the average between position 8th anf 9th and we got:

Median = \frac{1.31+1.46}{2}= 1.385

Part c

For this case we can assume that the mean is \mu = 1.3538

And we can calculate the population deviation with the following formula:

\sigma = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{N}}

And if we replace we got:  \sigma= 0.3105

And assuming normal distribution we have this:

X \sim N (\mu = 1.3538, \sigma= 0.3105)

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.1   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.28

And if we solve for a we got

a=1.3538 +1.28*0.3505=1.8024

So the value of height that separates the bottom 90% of data from the top 10% is 1.8024.  

Part d

The median is defined as :

Median= \frac{x_{8} +x_{9}}{2}

The variance for this estimator is given by:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} Var(X_{8} +X_{9})

We can assume the obervations independent so then we have:

Var(\frac{x_{8} +x_{9}}{2}) = \frac{1}{4} (2\sigma^2) = \frac{\sigma^2}{2}

And replacing we got:

Var(\frac{x_{8} +x_{9}}{2})= \frac{0.3105^2}{2}= 0.0482

And the standard error would be given by:

Sd(\frac{x_{8} +x_{9}}{2})= \sqrt{0.0482}=0.2196

6 0
2 years ago
Rectangle B is shown below. Nadia drew a scaled version of Rectangle B using a scale factor of = and labeled
Lina20 [59]

Answer:

The area of rectangle C is 2

Step-by-step explanation:

Using a scale factor of \frac{1}{5} yields the side lengths of 1 and 2

(1)(2)=2

4 0
2 years ago
Read 2 more answers
Judy built a rectangular patio that is 9 meters wide and has a perimeter of 40 meters what is the length of Judy’s patio
loris [4]
Hi !

<span><u>Judy built a rectangular patio that is 9 meters wide and has a perimeter of 40 meters what is the length of Judy’s patio ?</u></span>

l=9\;m\\L=x

So\;Perimeter=2(9+x)=18+2x=40\;m\\\\18+2x=40\\2x=40-18\\2x=22\\\\x=\dfrac{22}{2}\\\\\boxed{x=L=11}

The lenght of Judy's Patio is 11 meters.
3 0
1 year ago
A dog has dug holes in diagonally-opposite corners of a rectangular yard. One length of the yard is 8 meters and the distance be
LUCKY_DIMON [66]

For a better understanding of the solution provided please go through the diagram in the file attached.

Let ABCD be the rectangular yard. The diagonal d=17 meters. AD=8 meters. Therefore, the length of DC can be found by applying the Pythagorean theorem in the right triangle \Delta ADC as:

DC=\sqrt{17^2-8^2}=\sqrt{(AC)^2-(AD)^2}=\sqrt{225} =15 meters.

6 0
1 year ago
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