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STALIN [3.7K]
1 year ago
11

Question 9 20% of a particular brand of light bulbs fail in one year. What is the probability that three bulbs out of a random c

ollection of 8 bulbs fail in one year
Mathematics
1 answer:
Delvig [45]1 year ago
5 0

Answer:

The correct answer is 0.15

Step-by-step explanation:

According to the given scenario, the probability is as follows:

X\sim Bin (n,p)

Here

n = 8

p = 0.20 or 20%

Now this is a binomial probability distribution

P(X) = ^nC_x \times p^x \tmes (1 - p)^{n-x}\\\\P(3) = ^8C_3 \tims 0.20^3 \times (1 - 0.20)^5

= 0.15

Hence, the correct answer is 0.15

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Compare A and B if 70% of A is equal to $0.7a and 35% of B is equal to $0.35a
MrRa [10]

Answer:

A=B

Step-by-step explanation:

Equation 1: 70% of A = 0.7a

Equation 2: 35% of B = 0.35a

Equation 3 = (Equation 2) • 2

Equation 3: 70% of B = 0.7a

Equation 3 = Equation 1

A = B

3 0
2 years ago
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Consider circle C below, where the central angle is measured in radians. Circle C is shown. Line segments R C and S C are radii.
denis-greek [22]

What is the length of the radius?

12 units

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2 years ago
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Which of the following functions is graphed below?
dalvyx [7]

Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

- Add 4 to both sides

∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix + 5I = 4

∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

- OR

∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

5 0
2 years ago
Subway train arrives at the station every eight minutes you have a doctors appointment at the station so you take the subway and
topjm [15]
One min after it ends
8 0
2 years ago
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Write a quadratic function f whose zeros are 11 and 3 .
Harman [31]
Let the variable of the equation be x.

I'm gonna go backwards of the factorization process.

Given,

x = 11 or 3

(x - 11)(x - 3) = 0

x² -3x -11x + 33 = 0 

x² -14x + 33 = 0 

Hence, f(x) = x² - 14x + 33.
8 0
2 years ago
Read 2 more answers
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