With the sum of 99, we will get 50 pairs whole numbers. Why?
Let’s start with
0+ 99
1 + 98
2 + 97
3 + 96
4 + 95
5 + 94
6 + 93
7 + 92
8 + 91
9 + 90
10 + 89
………
……..
43 + 49
44 + 50
Therefore, if you’re going to count all pairs of whole number, you will get 50 pairs of whole number with the sum of 99.
Hope this helps!
Answer:
The 95% confidence interval for the percent of all coffee drinkers who would say they are addicted to coffee is between 21% and 31%.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

A confidence interval has two bounds, the lower and the upper
Lower bound:

Upper bound:

In this problem, we have that:

Lower bound:

Upper bound:

The 95% confidence interval for the percent of all coffee drinkers who would say they are addicted to coffee is between 21% and 31%.

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.
The null hypothesis is that there is not an average of 200 raisins per box.
I don't exactly know how to explain step 2 but the working is:
5 - 8x < 2x + 3
5 - 3 < 2x + 8x
2 < 10x
5 < x
(I'm sorry if it's wrong)