Given:
Total number of girls in her class = 16
Total number of boys in her class = 14
To find:
The number of different ways of choosing one girl and one boy.
Solution:
We have,
Total number of girls = 16
Total number of boys = 14
So,
Total number of ways to select one girl from 16 girls = 16
Total number of ways to select one boy from 14 boys = 14
Now, number of different ways of choosing one girl and one boy is
Therefore, the required number of different ways is 224.
In the game of cornhole, when Sasha tossed a bean bag to the edge of the hole, in which the equations of the hole and bean bag's path are x² + y² = 5 and y = 0.5x² + 1.5x - 4, respectively, she could have tossed her bean bag to the points (1, -2) or (2, 1).
To find the points in which she could have tossed her bean bag, we need to intersect the two equations of the function as follows.
<u>The equation for the hole</u>
(1)
<u>The equation for the path of the bean bag</u>
(2)
By entering equation (2) into (1) we have:
By solving for <em>x</em>, we have:
x₁ = 1
x₂ = 2
Now, for <em>y</em> we have (eq 2):
Therefore, the points are (1, -2) or (2, 1).
To find more about intersections, go here: brainly.com/question/4977725?referrer=searchResults
I hope it helps you!