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malfutka [58]
2 years ago
8

A survey of 250 households showed 26 owned at least one snow blower. Find a point estimate for p, thepopulation proportion of ho

useholds that own at least one snow blower.
0.094


0.116


0.104


0.896
Mathematics
1 answer:
lions [1.4K]2 years ago
3 0

Answer:

The population proportion of households that own at least one snow blower is 0.104.

Step-by-step explanation:

In order to find the population proportion of households that own at least one snow blower, you have to divide the number of people that said they owned at least one snow blower by the number of households surveyed:

26/250=0.104

According to this, the answer is that a point estimate for p, the population proportion of households that own at least one snow blower is 0.104.

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The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

The probability of getting two 3 as outcome is \frac{1}{4} \times\frac{1}{4} = \frac{1}{16}.

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is 1 - \frac{1}{4} = \frac{3}{4}.

Hence, the required probability is 15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}≅0.2966 or, 0.23.

4 0
2 years ago
Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge
ASHA 777 [7]
23 +30 (15 feet each way) = 53

28 + 30 = 58

58 x 53 = 3074ft
7 0
2 years ago
Read 2 more answers
A sports statistician was interested in the relationship between game attendance (in thousands) and the number of
Luda [366]

Answer:

The predicted number of wins for a team that has an attendance of 2,100 is 25.49.

Step-by-step explanation:

The regression  equation for the relationship between game attendance (in thousands) and the number of  wins for baseball teams is as follows:

\hat y = 4.9\cdot x + 15.2

Here,

<em>y</em> = number of wins

<em>x</em> = attendance (in thousands)

Compute the number of wins for a team that has an attendance of 2,100 as follows:

\hat y = 4.9\cdot x + 15.2

  =(4.9\times 2.1)+15.2\\=10.29+15.2\\=25.49

Thus, the predicted number of wins for a team that has an attendance of 2,100 is 25.49.

4 0
2 years ago
In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
FrozenT [24]

Answer: The length of segments between this point and the vertices of greater base are 7\frac{5}{7} and 18.

Step-by-step explanation:

Let ABCD is the trapezoid, ( shown in below diagram)

In which AB is the greater base and AB = 18 DC= 11, AD= 3 and BC = 7

Let P is the point where The extended legs meet,

So, according to the question, we have to find out : AP and BP

In Δ APB and Δ DPC,

∠ DPC ≅ ∠APB ( reflexive)

∠ PDC ≅ ∠ PAB    ( By alternative interior angle theorem)

And, ∠ PCD ≅ ∠ PBA  ( By alternative interior angle theorem)

Therefore, By AAA similarity postulate,

\triangle APB\sim \triangle D PC

Let, DP =x

⇒ \frac{3+x}{18} = \frac{x}{11}

⇒  33 +11x = 18x

⇒ x = 33/7= 4\frac{5}{7}

Thus, PD= 4\frac{5}{7}

But, AP= PD + DA

AP= 4\frac{5}{7}+3 =7\frac{5}{7}

Now, let PC =y,

⇒ \frac{7+y}{18} = \frac{y}{11}

⇒ 77 + 11y = 18y

⇒ y = 77/7 = 11

Thus, PC= 11

But, PB= PC + CB

PB= 11+7 = 18



7 0
2 years ago
Jason wants to purchase a new pair of shoes. He has $70 he is able to spend. A popular new pair of shoes are sold at the shoe st
Ghella [55]

Answer:

$72.76 Us Dollars

Step-by-step explanation:

1st I found out what 20% off of $85 was and it was $68 US Dollars then I had to add 7% of $68 US Dollars and it came out to $72.76

Please Mark Brainliest!!!!

8 0
2 years ago
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