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Ivahew [28]
2 years ago
8

Thomas is planning a trip to India. He is currently deciding which cities he would like to visit during his stay. The table belo

w shows possible cities for Thomas to visit, as well as how much money he expects to need at each one. All costs are given in Indian rupees (Rs.).
City
Cost (Rs.)
Jaipur
6,920
Mumbai
9,464
Thiruvananthapuram
9,160
Lucknow
5,276
Bhopal
8,268
Bhubaneswar
7,109
New Delhi
6,303
Bengaluru
6,735

Thomas had originally planned to visit Thiruvananthapuram, Mumbai, Bhubaneswar, and Bengaluru, but his budget of Rs. 25,300 makes that impossible. Which of the following itinerary changes will allow Thomas to stay within his budget? (Consider each option individually, rather than as a group.)

I. Swap Thiruvananthapuram for Jaipur and drop Bengaluru.
II. Drop Bhubaneswar.
III. Swap Mumbai for New Delhi, Thiruvananthapuram for Jaipur, and Bhubaneswar for Lucknow.
a.
I and II
b.
III only
c.
I and III
d.
I, II, and III
Mathematics
2 answers:
Serga [27]2 years ago
6 0

Answer:

C

Step-by-step explanation:

took the test got it right

Oksana_A [137]2 years ago
4 0
Swap Thiruvananthapuram for Jaipur and drop Bengaluru and  Swap Mumbai for New Delhi, Thiruvananthapuram for Jaipur, and Bhubaneswar for Lucknow.this option is cheaper for thomas
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Milk and cream are mixed together for a recipe. The total volume of the mixture is 1 cup. If the milk contains 2% fat, the cream
inessss [21]

Answer: 1/4

Step-by-step explanation:

Let the volume of mixture (6%fat) in cup is 100cc

x cc be the volume of cream (18% fat) in the mixture.

∴

(100−x) cc be the volume of milk (2% fat) in the mixture.

x * 0.18+(100−x) * 0.02=100

⋅0.06 or 0.18x − 0.02x = 6−2 or 0.16x

= 4 or x=25 cc = 25%

7 0
2 years ago
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After the closing of the mill, the town of Sawyerville experienced a decline in its population.
ycow [4]

Step-by-step explanation:

P(t) = 12,000 (2)^(-t/15)

9,000 = 12,000 (2)^(-t/15)

0.75 = 2^(-t/15)

ln(0.75) = ln(2^(-t/15))

ln(0.75) = (-t/15) ln(2)

-15 ln(0.75) / ln(2) = t

t = 6.23

5 0
2 years ago
calculeaza lungimea segmentului ab in fiecare dintre cazuri:A(1,5);B(4,5);A(2,-5),B(2,7);A(3,1)B(-1,4);A(-2,-5)B(3,7);A(5,4);B(-
Tatiana [17]

Answer:

1. 3; 2. 12; 3. 5; 4. 13; 5. 10; 6. 10

Step-by-step explanation:

We can use the distance formula to calculate the lengths of the line segments.

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}

1. A (1,5), B (4,5) (red)

d = \sqrt{(x_{2} - x_{1}^{2}) + (y_{2} - y_{1})^{2}} = \sqrt{(4 - 1)^{2} + (5 - 5)^{2}}\\= \sqrt{3^{2} + 0^{2}} = \sqrt{9 + 0} = \sqrt{9} = \mathbf{3}

2. A (2,-5), B (2,7) (blue)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(2 - 2)^{2} + (7 - (-5))^{2}}\\= \sqrt{0^{2} + 12^{2}} = \sqrt{0 + 144} = \sqrt{144} = \mathbf{12}

3. A (3,1), B (-1,4 ) (green)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-1 - 3)^{2} + (4 - 1)^{2}}\\= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = \mathbf{5}

4. A (-2,-5), B (3,7) (orange)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(3 - (-2))^{2} + (7 - (-5))^{2}}\\= \sqrt{5^{2} + 12^{2}} = \sqrt{25 + 144} = \sqrt{169} = \mathbf{13}

5. A (5,4), B (-3,-2) (purple)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-3 - 5)^{2} + (-2 - 4)^{2}}\\= \sqrt{(-8)^{2} + (-6)^{2}} = \sqrt{64 + 36} = \sqrt{100} = \mathbf{10}

6. A (1,-8), B (-5,0) (black)

d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} = \sqrt{(-5 - 1)^{2} + (0 - (-8))^{2}}\\-= \sqrt{(-6)^{2} + (-8)^{2}} = \sqrt{36 + 64} = \sqrt{100} = \mathbf{10}

6 0
2 years ago
The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x) = (e^-x/1076)/
kozerog [31]

Answer:

(a) 0.06154

(b) 0.2389

(c) 0.6052

(d) 2478

Step-by-step explanation:

probability density function of the time to failure of an electronic component in a copier (in hours) is

P(x) = 1/1076e^−x/1076

λ = 1/1076

A) A component lasts more than 3000 hours before failure:

P(x>3000) = 1 − e^−3000/1076

= 0.06154

B) A component fails in the interval from 1000 to 2000 hours:

P(1000>x>2000) =1 − e^−2000/1076 − 1 +e^−1000/1076 = e^−1000/1076 − e^−2000/1076 = 0.3948 − 0.1559

= 0.2389

C) A component fails before 1000 hours:

P(x<1000) = 0.6052

D) The number of hours at which 10% of all components have failed:

e^−x/1076 = 0.1

= −x/1076

= ln(0.1)

x =(2.3026)×(1076)

x = 2478

4 0
2 years ago
Modern Vehicles Company came up with two different plans for the next financial year. Plan Y: Increase vehicle production by 5%
ladessa [460]

Answer: plan Y will produce more vehicles after 4 years.

Step-by-step explanation:

1) Plan Y: Increase vehicle production by 5% every year. It means that the rate of production is in geometric progression. The formula for determining the sum of n terms, Sn of a geometric sequence is expressed as

Sn = (ar^n - 1)/(r - 1)

Where

n represents the number of term(years) in the sequence.

a represents the first term(number of vehicles in the present year) in the sequence.

r represents the common ratio.

From the information given,

a = 10000

r = 1 + 5/100 = 1.05

n = 4 years

Therefore, the sum of the vehicles produced in the first 4 years, S4 is

S4 = (10000 × 1.05^(4) - 1)/1.05 - 1

S4 = (10000 × 0.21550625)/0.05

S4 = 2155.0625/0.05

S4 = 43101 vehicles

2) Plan Z: Increase production by 300 vehicles every year. It means that the rate of production is in geometric progression. The formula for determining the sum of n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

From the information given,

n = 4 years

a = 10000

d = 300

Therefore, the sum of the first 4 terms, S4 would be

S4 = 4/2[10000 × 2 + (4 - 1)300]

S4 = 2[20000 + (3)300]

S4 = 2 × 20900

S4 = 41800 vehicles

6 0
2 years ago
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