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Yuri [45]
2 years ago
15

Astrid wants to buy pumpkins and watermelons. She wants to buy more than 101010 fruits, and she has a budget of \$117$117dollar

sign, 117. P+W > 10P+W>10P, plus, W, is greater than, 10 represents the number of pumpkins PPP and watermelons WWW Astrid should buy to get more than 101010 fruits. 5.5P+3.5W \leq 1175.5P+3.5W≤1175, point, 5, P, plus, 3, point, 5, W, is less than or equal to, 117 represents the number of pumpkins and watermelons she can buy on her budget of \$117$117dollar sign, 117. Does Astrid meet both of her expectations by buying 777 pumpkins and 333 watermelons?
Mathematics
1 answer:
julsineya [31]2 years ago
3 0

Answer:

D 5 pumpkins, 13 watermelons

Step-by-step explanation:

please give brainiest

0 pumpkins, 0 watermelons

7 pumpkins, 3 watermelons

5 pumpkins, 13 watermelons

5 pumpkins, 5 watermelons

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1 year ago
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a computer shop charges 20 pesos per hour (or a fraction of an hour) for the first two hours and additional 10 pesos per hour fo
Serhud [2]

Answer:

The equation for the price, as a function of time in hours is:

P(x) = 20*x    for 0 ≤ x ≤ 2

P(x) = 40 + 10*(x - 2)  for  2 ≤ x

Now, we want to evaluate this function in 40 mins.

we know that 1 hour = 60mins.

Then 40 mins = (40/60) hours = 0.67 hours.

Then we input this in our function, and because this is smaller than 2, we use the first piece of our function:

P(0.67) = 20*0.67 = 13.4

So in 40 mins, the charge will be 13.4 pesos.

7 0
1 year ago
Is the sum of the areas of two smaller squares equal to the area of a large square if the sides lengths of the squares are 8 fee
77julia77 [94]
No.
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5 0
1 year ago
If a certain number is increased by 5 one half of the result is three-fifths of the excess of 61 over the number find the number
PSYCHO15rus [73]

Answer:

= 391/11

Let say number = N

a certain number is increased by 5

= N + 5

,one-half of the result

= (N + 5)/2

Three -fifths of the excess of 61 over the number.

= (3/5)(61 - N)

Equating both

(N + 5)/2  = (3/5)(61 - N)

multiplying by 10 both sides

=> 5(N + 5) = 6(61 - N)

=> 5N + 25 = 366 - 6N

=> 11N = 391

=> N = 391/11

Step-by-step explanation:

8 0
1 year ago
Two wires with lengths of 448 cm and 616 cm are to be cut into pieces of all the same length without a remainder. Find the great
Y_Kistochka [10]

Answer:

56 cm

Step-by-step explanation:

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The factors of 616=2*2*2*7*11

The factors of 448 =2*2*2*2*2*2*7

Common factors in both are 2*2*2*7=56

Therefore, the greatest possible length is 56 cm

6 0
2 years ago
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