If we look at where it is now, we would have multiplied the x and y values by 1/2. since we are working backwards, lets multiply by 2 instead...giving us the vertex for the pre-image....
J is now (0, -2) multiply by 2
J was (0, -4)
1/2 + 1/5(1/2) = 1/2 + 1/10 = 5/10 + 1/10 = 6/10....this leaves 4/10 (reduces to 2/5) for his children.
(2/5) / 3 = 2/5 * 1/3 = 2/15 for each child <== A
400 in each childs account.....thats (400 * 3) = 1200 ...
2/5 of what is 1200 =
2/5x = 1200
x = 1200 * 5/2
x = 6000/2
x = 3000 <== B
check...
total pay is 3000
1/2 for bills.....- 1500
1/5(-1500) = -1500/5 = -300 ....for savings
3000 - (1500 + 300) = 3000 - 1800 = 1200...remaining for the children
1200/3 = 400 ...for each child.
so ur answers are :
A. 2/15 in each childs account
B. original paycheck = $ 3000
Answer:
he can expect to lose 0.5$
Step-by-step explanation:
To solve this problem we must calculate the expected value of the game.
If x is a discrete random variable that represents the gain obtained when rolling a dice, then the expected value E is:

When throwing a dice the possible values are:
x: 1→ -$9; 2→ $4; 3→ -$9; 4→ $8; 5→ -$9; 6→ $12
The probability of obtaining any of these numbers is:

The gain when obtaining an even number is twice the number.
The loss to get an odd number is $ 9
So the expected gain is:

Hello :
<span>an equation of the circle Center at the
w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
In this exercice : (x-3)²+y²=7² ....a =3 and b=0 ( the center is :w(3,0)) ... r=7
The distance between each point in each case is calculated and compared with the length of the radius
1 ) </span>A (-1, 1) : Aw² = (-1-3)²+1² =17..... Aw < r : <span>interior the circle
</span> 2 ) B(10, 0) :Bw² =(10-3)²+0² =49 ......r = Bw :<span>circumference of the circle
</span> 3 ) C(4, -8) :Cw² = (4-3)²+(-8)² =65..... Cw > r : exterior the circle
d = 58h + 256
Let me know if you need me to explain this! :)