We have to find the" ratio of the area of sector ABC to the area of sector DBE".
Now,
the general formula for the area of sector is
Area of sector= 1/2 r²θ
where r is the radius and θ is the central angle in radian.
180°= π rad
1° = π/180 rad
For sector ABC, area= 1/2 (2r)²(β°)
= 1/2 *4r²*(π/180 β)
= 2r²(π/180 β)
For sector DBE, area= 1/2 (r)²(3β°)
= 1/2 *r²*3(π/180 β)
= 3/2 r²(π/180 β)
Now ratio,
Area of sector ABC/Area of sector DBE =
= 4/3
Answer:
-7k + 14
Step-by-step explanation:
(k² - 7k + 2) - (k² - 12)
k² - 7k + 2 - k² + 12
k² - k² - 7k + 2 + 12
-7k + 14
<span>A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. What is the train’s original speed?
***
let x=original speed
x+5=increased speed
travel time=distance/speed
..
lcd:x(x+5)
150(x+5)-150x=x(x+5)
150x+750-150x=x^2+5x
x^2+5x-750=0
(x-25)(x+30)=0
x=25
What is the train’s original speed? 25 mph</span>
Answer:
C
Step-by-step explanation:
The polynomial on the graph has zeros or x-intercepts at x = -3, 0, 2, 4. These come from the factors x (x+3)(x-2)(x-4). Notice at 4 it doesn't cross but just touches. This means it has a degree of 2. So the factors are 
. This matches to C.
Answer:
15%
Step-by-step explanation:
To find the percent increase, use the equation:
percent of increase=<u>amount of increase</u>
original amount
The amount of increase is 92-80 = 12. The original amount of 80; this gives us
12/80 = 0.15 = 15%
