The question is incorrect.
The correct question is:
Three TAs are grading a final exam.
There are a total of 60 exams to grade.
(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?
Answer: 60!/(25!20!15!)
Step-by-step explanation:
The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’
n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1
The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:
n!/p! q! r!
Therefore,
The answer is 60!/25!20!15!
Answer:
60
Step-by-step explanation:
Answer:
2801 boxes
Step-by-step explanation:
You have 1 red box
You have 7 blue boxes, so far 8 boxes
There are 49 total black boxes (7*7), making 57 total boxes
There are 49*7 = 343 yellow boxes, making 400 boxes
There are 343*7 = 2401 gold boxes, making for a total of 2801 boxes.
Answer:
A) The theoretical probability of choosing a heart is 1/16 greater than the experimental probability of choosing a hear
Step-by-step explanation:
Answer:
Option D. 5890.5 feet²
Step-by-step explanation:
An individual head of a sprinkler system covers a circular are of grass with a radius of 25 feet.
Yard has three sprinkler heads that each cover circular area with no overlap.
We have to calculate the approximate area watered by these 3 sprinkler heads.
Area covered by one sprinkler = π×r² = π×(25)² = 625π feet²
Therefore area covered by three sprinkler heads = 3 × 625π = 5892.85 feet²
which matches the approximate value of Option D. 5890.5 feet²