Answer:
27.385 cm longer would we expect Mike's arm span to be than George's.
Step-by-step explanation:
We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:
y= 4.5x + 0.977 x
where y= arm span
and x= height
Given:
Mike's height=x = 175 cm
so Mike's arm span= y= 4.5 x + 0.977 x
= 4.5* (175) + 0.977* (175)
= 787.5 + 170.975
= 958.475 cm
George's height = x = 170 cm
so George's arm span= y= 4.5 x + 0.977 x
= 4.5* (170) + 0.977* (170)
= 765 + 166.09
= 931.09 cm
Mike's arm span longer than George's = Mike's arm span - George's arm span
= 958.475 - 931.09
= 27.385 cm.
To solve this question, you just need to count all the probability of the options.
The probability that a pitch not over the plate is a strike is zero. So, P(A | D) = 0.
True. It is 0/0+20= 0
The probability that a pitch not over the plate is a ball is 1. So, P(B | D) = 1.
True, it is 20/20+0= 1
The probability that a pitch over the plate is a strike is 10:15. So, ...
Incomplete but it sounds to be true. It should be 10/10+5= 10/15 = 2/3
The probability that a pitch over the plate is a ball is 5:10. So, P(B | C) = 0.5.
You would have to do 18.75/30%
=75/4*100/30=125/2
<span>f(x)=x^2+6x+3
=(1/2.6)^2=3^2=9
f(x)=(x2^+6x+9)+3-9
=(x+3)^2-6</span>
A group of customer service surveys were sent out at random. The scores were 90, 50, 70, 80, 70, 60, 20, 30, 80, 90, and 20. Fin
egoroff_w [7]
Answer:
60
Step-by-step explanation:
To find the mean, add all numbers together and divide by the amount of numbers.
Total of number = 660
Number of numbers = 11
660/11 = 60
