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svp [43]
2 years ago
15

How much of a 90% alloy must be combined with 70% gold alloy in order to get 60 ounces of an 85% gold alloy?

Mathematics
1 answer:
Umnica [9.8K]2 years ago
4 0
X = amount of 90% alloy
y = amount of 70% alloy

x + y = 60
0.9x + 0.7y = 0.85*60

0.9x + 0.7(60 - x) = 0.85*60
(0.9 - 0.7)x = (0.85 - 0.7)*60
x = (0.85 - 0.7)*60/(0.9 - 0.7)
x = 45 ounces

y = 60 - 45
y = 15 ounces
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In a science test devi scores 15 marks more than lixin . If devi obtains twice as many marks as lexin . Find the number of marks
BabaBlast [244]

Answer:

Lixin obtains 15 marks

Step-by-step explanation:

Lets write two equations based on the question where: <u>D= Devi and L=Lixin</u>

D=L+15 <em>- "devi scores 15 marks more than lixin"</em>

D=2L <em>- "devi obtains twice as many marks as lexin"</em>

Now, substitute 2L as D in the first equation we wrote: (D=L+15)

2L=L+15

Next, subtract L from both sides:

<u>L=15</u>

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the length of the highway is 1500 miles. If 1 inch represents 150 miles, what is the length of the highway on the map?
NeX [460]

Answer:

10 inches.

Step-by-step explanation:

If 1 inch represents 150 miles, and there are 1500 miles covered by the map, then the length of the highway on the map is 10 inches.

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The function f is continuous son the interval [2, 10] with some of its values given in the table below. Use a right Riemann Sum
Marta_Voda [28]

The 4 subintervals are given: [2, 4], [4, 7], [7, 9], and [9, 10].

Each subinterval has length: 4 - 2 = 2, 7 - 4 = 3, 9 - 7 = 2, and 10 - 9 = 1.

Over each subinterval, we take the value of the function at the right endpoint: 3, 8, 15, and 18.

Then the integral is approximately

\displaystyle\int_2^{10}f(x)\,\mathrm dx\approx3\cdot2+8\cdot3+15\cdot2+18\cdot1=78

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2 years ago
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Step-by-step explanation:

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A 92.0 kg football player at 6.50 m/s North collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg foot
s2008m [1.1K]

Answer:

-1.13 m/s

Step-by-step explanation:

Parameters given:

Mass of first footballer, M = 92 kg

Initial velocity of first footballer, U = 6.5 m/s (taking North to be the +ve y axis)

Mass of second footballer, m = 85 kg

Initial velocity of second footballer, u = -6.0 m/s (taking South to be the -ve y axis)

Final velocity of first footballer, V = 2.0 m/s

We need to find the final velocity of the second football (v)

Applying the principle of conservation of momentum, we have that, in a system:

Total Initial Momentum = Total Final Momentum

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=> v = -96 / 85

v = -1.13 m/s

The final velocity of the 85 kg player is -1.13 m/s i.e 1.13 m/s South

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