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satela [25.4K]
2 years ago
14

if the survey, 9/25 of students ride the bus to school and 19/50 walk to school. what fraction of students ride the bus or walk

to school
Mathematics
1 answer:
Elena-2011 [213]2 years ago
6 0

1. \dfrac{9}{25} of students ride the bus to school. Note that

\dfrac{9}{25}=\dfrac{9\cdot 2}{25\cdot 2}=\dfrac{18}{50}.

2. \dfrac{19}{50} of students walk to school.

3. The fraction of students that ride the bus or walk to school is

\dfrac{18}{50}+\dfrac{19}{50}=\dfrac{18+19}{50}=\dfrac{37}{50}.

Answer: the fraction of students that ride the bus or walk to school is \dfrac{37}{50}.

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Answer:

3 customers brought all the three papers.

Step-by-step explanation:

Let, D, O and N represents the three newspapers.

D = The daily times

O = The observer

N = The new Nigeria.

According to the given information,

n(D\cup O\cup N)=135, n(D)=70,n(O)=60,n(N)=50

n(D\cap O)=17, n(O\cap N)=15, n(D\cap N)=16

We know that,

n(A\cup B\cup C) = n(A) + n(B) + n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A) + n(A\cap B\cap C)

Using this formula, we get

n(D\cup O\cup N) = n(D)+n(O) + n(N)-n(D\cap O)-n(O\cap N)-n(N\cap D) + n(D\cap O\cap N)

135 =70+60+50-17-15-16 +n(D\cap O\cap N)

135 =132+n(D\cap O\cap N)

135 -132=n(D\cap O\cap N)

3=n(D\cap O\cap N)

Therefore, 3 customers brought all the three papers.

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2 years ago
Ahmed and Gavin are playing both chess and checkers. The probability of Ahmed winning the chess game is 45\%45%45, percent. The
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Step-by-step explanation:

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A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be
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Answer:

\$6,082.70  

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

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P=\$15,300\\r=14.25\%=0.1425\\x=6\ years

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V=15,300(1-0.1425)^{6}  

V=15,300(0.8575)^{6}  

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