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Stolb23 [73]
2 years ago
13

A 40-meter-long blade of a wind turbine makes one complete revolution in 10 seconds. To the nearest tenth, the linear velocity o

f the blade is ____meters per second.

Mathematics
2 answers:
Pani-rosa [81]2 years ago
7 0
The distance the tip travels is
  2π·(40 m) = 80π m

Then its speed is
  (80π m)/(10 s) = 8π m/2 ≈ 25.1 m/s
aliya0001 [1]2 years ago
4 0

Answer:

The answer is 25.1 m/s

Step-by-step explanation:

In order to determine the linear velocity of the blade, we have to know about circles.

In any circle, the expression of its perimeter is:

P=2\pi R

Where:

P=Perimeter of the circle

R=Radius of the circle.

To determine the linear velocity, first we have to determine the perimeter that the long blade describes.

The long blade lengths 40 meters. This value represents the radius of the circle movement. Then the perimeter is:

R=40\\P=2\pi (40)\\P=80\pi

Then, the linear velocity is the rate of the perimeter per one complete revolution:

V=\frac{P}{T}=\frac{80\pi }{10}=8*3.142=25.136

We have to round the final value to the nearest tenth. I have attached an image that shows the position of the nearest tenth.

Finally, the linear velocity is 25.1 m/s.

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Alicia buys a 5 pound bag of rocks for a fish tank. She uses 1 1/8 pounds of small fish bowl. How much is left?
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5-1 and 1/8=
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2 years ago
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If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs
sammy [17]

Answer:

QS=68\ units

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

8x-43=(2x-4)+(4x-1)

8x-43=6x-5

8x-6x=43-5

2x=38

x=19

step 2

Find the value of RS

RS=2x-4

substitute the value of x

RS=2(19)-4

RS=34\ units

step 3

Find the value of QS

Remember equation A

QS=2RS

so

QS=2(34)=68\ units

6 0
2 years ago
What is the answer to 13p12=
tiny-mole [99]

Answer:

156p

Step-by-step explanation:

13p×12

multiply the numbers

= 156p

8 0
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Louden County Wildlife Conservancy counts butterflies each year. Data over the last three years regarding four types of butterfl
MrRa [10]

Incomple question. However, here's the remaining part of the question:

14

2009

Meadow Fritillary= 5

Variegated Fritillary= 7

Zebra Swallowtail= 33

Eastern-Tailed Blue= 242

Louden County Butterfly Count

2010

Meadow Fritillary 34

Variegated Fritillary 95

Zebra Swallowtail 21

Eastern-Tailed Blue 168

2011

Meadow Fritillary

Variegated Fritillary

Zebra Swallowtail

Eastern-Tailed Blue

10

170

<u>Options</u>:

A) All butterfly populations are steadily decreasing.

B)All butterfly populations were larger than usual in 2010.

C)The Eastern-Tailed Blue butterfly is more common than the others.

D)The Meadow Fritillary is equally common as the Variegated Fritillary

Answer:

<u>C</u>

Step-by-step explanation:

Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.

Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.

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2 years ago
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