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SOVA2 [1]
2 years ago
15

Mrs Atkins is going to choose two students from her class to take part in a competition.

Mathematics
1 answer:
Schach [20]2 years ago
6 0

Given:

Total number of girls in her class = 16

Total number of boys in her class = 14

To find:

The number of different ways of choosing one girl and one boy.

Solution:

We have,

Total number of girls = 16

Total number of boys = 14

So,

Total number of ways to select one girl from 16 girls = 16

Total number of ways to select one boy from 14 boys = 14

Now, number of different ways of choosing one girl and one boy is

16\times 14=224

Therefore, the required number of different ways is 224.

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Translation can't change angles or lengths.  And if those don't 
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8 0
1 year ago
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11. S(-4,-6) and T(-7, -3); Find R.<br> What is the missing endpoint if S is the midpoint of RT
Nezavi [6.7K]

answer is (-7,-9)

step by step:-

S is the midpoint of RT so ,

s=\frac{R+T}{2 }

-4=\frac{x-7}{2}  ,     -6=\frac{y-3}{2}

-14=x-7  ,   -12=y-3

x=-7          ,    y=-9

R= (-7,-9)

5 0
1 year ago
Javier writes an integer on a piece of paper. The absolute value of his number is less than 4. Which is true of the possible val
ANTONII [103]
<span>The possible values are less than 4 but greater than –4.</span>
7 0
1 year ago
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Suppose that public opinion in a large city is 55% in favor of increasing taxes to support renewable energy and 45% against such
Harman [31]

Answer:

The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>

                                              √0.45*0.55/600

The right answer is B.

Step-by-step explanation:

According to the given data we have the following:

sample size, h=600

probability against increase tax p=0.45

The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.

We find that P(P>360/600)=P(P>0.6)

The sample proposition of p is approximately normally distributed mith mean p=0.45

standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600

If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)

Now, P(P>0.6)=P(<u>P-P</u>   >     <u>0.6-0.45)</u>

                             σ          √0.45*0.55/600

=P(Z> <u>0.6-0.45)</u>

       √0.45*0.55/600

8 0
2 years ago
Oni was timing her 100 meter sprints. Her first five sprints were 12.568 seconds, 11.426 seconds, 12.324 seconds, 11.981 seconds
oksian1 [2.3K]

Answer:

Rounding to the nearest tenth and rounding to the nearest one hundredth.

Step-by-step explanation:

round all up or down then  line up and add

12.568= 13

11.426=  11

12.324= 12

11.981=  12

12.601= 13

add the totals then you see

60.83 sames as 61

4 0
1 year ago
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