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Sloan [31]
2 years ago
11

The marketing department at Cable TV (CTV) wants to know how promotional advertising affects the number of viewers for the Satur

day Night Movie. Research shows that 10 million viewers watched the movie when CTV ran 15 one-minute ads on Friday. When they ran 25 one-minute ads on Friday, the movie had 18 million viewers. Use linear interpolation to estimate the number of viewers if CTV runs 23 one-minute ads on Friday.
Mathematics
1 answer:
Ilya [14]2 years ago
7 0

Answer:

  16.4 million viewers

Step-by-step explanation:

The number of viewers increased by 8 million from 10 to 18 million when the number of ads increased by 10 ads from 15 to 25. If 23 ads are run, that represents an increase of 8 ads from 15, so we expect 8/10 of the increase in viewers.

  8/10 × 8 million = 6.4 million

The number we expect with 23 ads is 6.4 million more viewers than 10 million viewers, so is 16.4 million.

_____

<em>Alternate solution</em>

We can write a linear equation in 2-point form for the number of viewers expected for a given number of ads:

  y = (18 -10)/(25 -15)(x -15) +10

  y = (8/10)(x -15) +10

  y = 0.8x -2 . . . . . million viewers for x ads

For 23 ads, this gives ...

  y = 0.8×23 -2 = 18.4 -2 = 16.4 . . . . million viewers, as above

_____

<em>Comment on 8/10</em>

I consider it coincidence that the number 23 is 8/10 of the difference between 25 and 15, and the slope of the line is 8/10. The point we're trying to interpolate has no relationship to the slope of the line, and vice versa.

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Ralph is estimating the cost of concrete to build a slab. The slab will have a length of 12 feet, a width of 9 feet, and a thick
snow_lady [41]

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$20196

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2 years ago
Caleb draws 14 dogs on each of 4 posters.He draws 18 cats on each of 6 other posters. If he draws 5 more dogs on each poster wit
MatroZZZ [7]
Caleb draws 14 dogs on each of 4 posters.
Then,
Number of dogs drawn by caleb in the first instance = (14 * 4) dogs
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Celeb drew 18 cats on each of 6 other posters.
Then
Number of cats drawn by Caleb in the first instance = (18 * 6) cats
                                                                                   = 108 cats
Again Caleb draws 5 more dogs on each poster with dogs.
Then,
The number of Dogs drwn in the second instance = (5 * 4) dogs
                                                                                 = 20 dogs
So, the total number of dogs drawn by Caleb = ( 56 + 20) dogs
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Then the total number of cats and dogs drawn by Caleb = 108 + 76
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5 0
2 years ago
injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and ri
diamong [38]

Answer:

The length of the track is approximately 51.7 ft

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has <u>three</u> sides of the square and the distance round <u>a half of a</u> complete circle.

5 0
2 years ago
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