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2 years ago

If a 10-pound turkey costs $20.42.how much does a 21-pound turkey cost

Mathematics

1 answer:

sergij07 [2.7K]2 years ago

6 0

Answer:

$42.88

Step-by-step explanation:

Let's create a proportion using the following setup:

cost/pounds=cost/pounds

We know that it costs $20.42 for a 10 pound turkey.

$20.42/10 pounds= cost/pounds

We don't know how much a 21 pound turkey costs, so we can say that it costs $x for a 21 pound turkey.

$20.42/ 10 pounds= $x/ 21 pounds

20.42/10=x/21

We want to find x, by getting x by itself.

x is being divided by 21. The inverse of division is multiplication. Multiply both sides by 21.

21*(20.42/10)=(x/21)*21

21* 20.42/10=x

21*2.042=x

42.882=x

Round to the nearest cent, or hundredth.

42.88=x

x= $42.88

A 21 pound turkey costs $42.88

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1 year ago

Read 2 more answers

Can someone help please

riadik2000 [5.3K]

Answer:

62 Sunday papers were sold

Step-by-step explanation:

Let x represent the number of Sunday papers sold. Then half that many, or x/2, is the number of Friday papers sold. The total revenue from the sales is the sum of products of quantity and price:

1.50 · x + 0.75 · (x/2) = 116.25

Multiplying by 2, this becomes ...

3.00x +0.75x = 232.50

3.75x = 232.50

Dividing by the coefficient of x gives ...

232.50/3.75 = x = 62

The number of Sunday newspapers sold is 62.

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2 years ago

Of the 100 students enrolled at the dance studio, 50 take ballet and 24 take tap dancing. Eight of the students who take ballet

Soloha48 [4]

Answer:

42 over 100

Step-by-step explanation:

8 0

2 years ago

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One week, Claire earned $272.00 at her job when she worked for 17 hours. If she is paid the same hourly wage, how many hours wou

DochEvi [55]

Answer: 448 hours

Step-by-step explanation:

272 divided by 17 = hourly wage

hourly wage= 16$

448 divided by 16 = 28 weeks

28 x 16= 448 hours

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2 years ago

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Two armadillos and three aardvarks sat in a five-seat row at the Animal Auditorium. What is the probability that the two animals

Serhud [2]

Answer:

$\dfrac{1}{15}$

Explanation:

The number of different ways in which the two armadillos would be at the ends of the row is 2:

$P(2,2)=\dfrac{2!}{(2-2)!}=\dfrac{2}{0!}=2$

The number of different combinations in which two of the three aardvarks can sit at the ends of the row is P(3,2):

$P(3,2)=\dfrac{3!}{(3-2)!}=\dfrac{3\times 2\times 1}{1}=6$

Therefore, there are 2 + 6 = 8 different ways in which the two animlas on the ends of the row were both armadillos or both aardvarks.

Now calculate the total number of different ways in which the animals can sit. It is P(5,5):

$P(5,5)=\dfrac{5!}{(5-5)!}=5!=5\times 4\times 3\times 2\times 1=120$

Thus, the probability that the two animals on the ends of the row were both armadillos or both aardvarks is equal to the number of favorable outputs divided by the total number of possible outputs:

$Probability=\dfrac{8}{120}=\dfrac{1}{15}$

8 0

1 year ago