Given:
PV = 13,440
i = 5.86% , compounded monthly
t = 4 years
13,440(0.0586/12))/(1-(1+0.0586/12)^-48= 15,109.44
15,109.44 + 156.60 = 15,266.04
15,266.04 - 13,440.00 = 1,826.04
<span>1,826.04/15,266.04 = 11.96 % Percentage total of Finance Charge of the total loa</span>
Answer:
-45
Step-by-step explanation:
-34+15=-19
-29-(-3)= -29+3= -26
-19 + -26 = -45
Answer:
Step-by-step explanation:
Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.
m∠2 = 50°
m∠1 + m∠2 = 180° [Linear pair of angles]
m∠1 = 180° - 50°
m∠1 = 130°
m∠3 = m∠1 = 130° [Vertically opposite angles]
m∠3 + m∠5 = 180° [Consecutive interior angles]
m∠5 = 180° - m∠3
= 180° - 130°
= 50°
m∠6 + m∠5 = 180° [Linear pair of angles]
m∠6 = 180° - 50° = 130°
Wei la dooblave hexagono 8 solutes x n o solutes = questionnairre
Answer:
-95.78
Step-by-step explanation:
As the researcher decided to make the number of parties attended per week the explanatory variable, this would be variable x in the regression line, and of course, the variable y would be the number of text messages sent per day.
After constructing the linear regression equation, the researcher found that an approximate value
for the actual value of y could be represented by the line
Since this is an approximate value, it is not expected that it coincides with the actual value of y. We define then the residual for each value of x as the difference between the actual value of y and the approximation for the given x.
For the value x = 2 (the student attended 2 parties that week) the actual value of y is 20 (the student sent 20 text messages per day that week).
The approximate value of y would be according to the regression line
Hence, the residual value for x=2 would be