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Zina [86]
2 years ago
12

If a 10-pound turkey costs $20.42.how much does a 21-pound turkey cost

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
6 0

Answer:

$42.88

Step-by-step explanation:

Let's create a proportion using the following setup:

cost/pounds=cost/pounds

We know that it costs $20.42 for a 10 pound turkey.

$20.42/10 pounds= cost/pounds

We don't know how much a 21 pound turkey costs, so we can say that it costs $x for a 21 pound turkey.

$20.42/ 10 pounds= $x/ 21 pounds

20.42/10=x/21

We want to find x, by getting x by itself.

x is being divided by 21. The inverse of division is multiplication. Multiply both sides by 21.

21*(20.42/10)=(x/21)*21

21* 20.42/10=x

21*2.042=x

42.882=x

Round to the nearest cent, or hundredth.

42.88=x

x= $42.88

A 21 pound turkey costs $42.88

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Answer:

the new scale is the same length as the original scale

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2 years ago
Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production
Whitepunk [10]

Answer:

32% probability of a defect.

The expected number of defects for a 1000-unit production run is 320.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 10

Standard deviation = 0.15.

Probability of a defect

Weights less than 9.85 oz or greater than 10.15 oz will be classified as defects.

9.85 = 10 - 0.15

10.15 = 10 + 0.15

By the Empirical Rule, 68% of weights are between 9.85 and 10.15, that is, within the limits. 32% are not within the limits.

So there is a 32% probability of a defect.

Expected number of defects for a 1000-unit production run.

E(X) = 0.32*1000 = 320

The expected number of defects for a 1000-unit production run is 320.

5 0
2 years ago
Jessica is 5 years older than her sister Jenna. Jenna tells her sister that in 5 years, she will be as old as Jessica was 5 year
emmasim [6.3K]
                          Jenna's age                   Jessica's age

today                         x                               x + 5


in 5 years                 x+5 

5 years ago                                                   x + 5 - 5


Equality                  x + 5 = x + 5 - 5

=> x + 5 = x


The equation is x + 5 = x


That equation has not any solution, because it reduces to 5 = 0, which is an absurd.


So, the conclusion is that information given by Jenna is wrong.


It is logical: if the difference of the ages is 5, in five years Jenna will have 10 years more than what her sister had 5 years ago, no 5 as she told Jessica.
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2 years ago
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Answer: C. 461

Step-by-step explanation:

We know that the formula to find the sample size is given by :-

n=(\dfrac{z^*\cdot \sigma}{E})^2

, where \sigma = Population standard deviation from prior study.

E = margin of error.

z* = Critical value.

As per given , we have

\sigma=125

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Critical value (Two tailed)=z^*=z_{\alpha/2}=z_{0.005}=2.576

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Hence, the required sample size to be taken is 461.

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