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Alika [10]
1 year ago
8

What are the possible values of x and y for two distinct points, (5, –2) and (x, y), to represent a function?

Mathematics
2 answers:
netineya [11]1 year ago
7 0
X may have any value except 5.
y may have any value.
AysviL [449]1 year ago
5 0

Answer:

Possible values of x and y can be:

x can be any value except 5

and y can be any value

Step-by-step explanation:

A function f is a map from a non empty set A to B if every element of a is mapped to a unique element of B.

Here we are given that:

f(5)= -2

for two distinct points such that f(x)=y

x can be any value except 5

(since 5 has a image -2 and for a function image of any element is unique)

and y can be any value

Possible values of x and y can be:

x can be any value except 5 and y can be any value

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The two conditional relative frequency tables show the results of a neighborhood survey on the number and types of gardens in th
Basile [38]

C.

Because the given condition required to have a flower garden first and then the probability of having a vegetable garden is calculated.

7 0
1 year ago
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A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat
vivado [14]
Analysis to obtain the function that models the polulaiton ob bees:

1) First year 9,000 bees

2) Second year: decrease 5% => 9,000 - 0.05* 9,000 = 9,000 * (1 - 0.05) = 9,000 * 0.95

3) Every year the population decreases 5% => 9,000 * 0.95)^ (number of years)

4) if you call x the number of years, and f(x) the function that represents the number of bees, then: f(x) = 9,000 (0.95)^ x.

Analysis of the statements:

<span>1) The function f(x) = 9,000(1.05)x represents the situation.

FALSE: WE DETERMINED IT IS f(x) = 9,000 (0.95)^x

2) The function f(x) = 9,000(0.95)x represents the situation.

TRUE: THAT IS WHAT WE OBTAINED AS CONCLUSION OF THE PREVIOUS ANALYSIS.

3) After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.

Do the math:

f(2) = 9,000 * (0.95)^2 = 9,000 * 0,9025 = 8,122

So, the statement is TRUE

4) After 4 years, the farmer can estimate that there will be about 1,800 bees remaining.

f(4) = 9,000 * (0.95)^4 = 9,000 * 0.81450625 = 7,330

So, the statement is FALSE

5) The domain values, in the context of the situation, are limited to whole numbers.

FALSE: THE DOMAIN VALUES ARE ALL NON NEGATIVE REAL VALUES. FOR EXAMPLE THE FUNCTION IS WELL DEFINED FOR X = 5 AND HALF

6) The range values, in the context of the situation, are limited to whole numbers.

TRUE: THERE CANNOT BE FRACTIONS OF BEES
</span>
3 0
2 years ago
Read 2 more answers
What is the best approximation of the projection of (2,6) onto (5,-1)
Darya [45]

Answer:

0.15(5,-1)

Step-by-step explanation:

\frac{v_{1} * v_{2} }{|v_{2}|^{2} }*v_{2}  ⇒ \frac{(2)(5)+(6)(-1)}{\sqrt{5^2+(-1)^2} }(5,-1) ⇒  \frac{4}{26} (5,-1)  ⇒  0.15(5,-1)

5 0
1 year ago
A metal rod is 25.000cm long at 25.0 degrees Celsius. When heated to 102.0 degrees Celsius, it is 25.054 cm long. What is the co
inn [45]
<span>You may deduce what it represents by analyzing the formula you just wrote.
Well, </span>the coefficient of linear expansion as the fractional change in length per degree of temperature change. 

ΔL = c x L(initial) x ΔT 

where c is the coefficient of linear expansion. You can rewrite the equation to give you c. 

c = ΔL / [L(initial) x ΔT] 

<span>Just substitute the variables and the answer will be
c = 0.000028. </span>

Now, what it represents.It may represent the extent to which the rod expands with temperature when compared to its original length. 
6 0
2 years ago
Read 2 more answers
The weights of items produced by a company are normally distributed with a mean of 5 ounces and a standard deviation of 0.3 ounc
Anastaziya [24]

Answer:

The value is x = 5.0744 \ ounce

Step-by-step explanation:

From the question we are told that

  The mean is  \mu  = 5 \ ounce

  The standard deviation is \sigma =  0.3 \ ounce

  Generally the minimum weight of the heaviest 9.8% is mathematically represented as

    P(X  > x ) =P( \frac{X - \mu}{\sigma } >  \frac{x -5}{0.3}  ) =  0.098

=> P(X  > x ) =P( Z >  \frac{x -5}{0.3}  ) =  0.098

From the normal distribution table  the z-score  for 0.098 is  

   z =0.248

So

     \frac{x -5}{0.3} = 0.248

=>   x = 5.0744 \ ounce

5 0
1 year ago
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