If you do not mind me asking, what did Seth write? Us helpers cannot answer it if we do not have the full question. I apologize if this seems rude.
The function of the trapezoid area is:
A(x)=(B+b)*h/2
Where B and b are the bases and h is the height.
With the given data: h=10 B and b =7 and x (it may vary which one is bigger)
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So that function becomes:
A(x)=(7+x)*10/2
A(x)=(7+x)*5
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So if you want the inverse function, you have to operate to find x:
A(x)/5=7+x
A(x)/5-7=x
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So the new function is:
x(A)=A/5-7
Answer:b)0.8577
Step-by-step explanation:
Since the heights of men are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = heights of men
u = mean height
s = standard deviation
From the information given,
u = 69 inches
s = 2.8 inches
We want to find the probability that the mean height of the 100 men is less than 72 inches.. It is expressed as
P(x < 72)
For x = 72
z = (72 - 69)/2.8 = 1.07
Looking at the normal distribution table, the probability corresponding to the z score is 0.8577
P(x < 72) = 0.8577
Answer:
A) The probability is 0.95 that the percent of adults living in the United States who are satisfied with their health care plans is between 63.6% and 68.4%.
Step-by-step explanation:
A polling agency reported that 66 percent of adults living in the United States were satisfied with their health care plans. The estimate was taken from a random sample of 1,542 adults living in the United States, and the 95 percent confidence interval for the population proportion was calculated as (0.636, 0.684).
This means that we are 95% sure that the true proportion of adults living in the United States who were satisfied with their health care plans is between 0.636 and 0.684.
So the correct answer is:
A) The probability is 0.95 that the percent of adults living in the United States who are satisfied with their health care plans is between 63.6% and 68.4%.
