What comes after 93 27 14.

Suppose we have two thermometers. One thermometer is very precise but is delicate and heavy (X). We have another thermometer tha

makvit [3.9K]

Answer:

Step-by-step explanation:

(a) H0: μ_D=0

Ha: μ_D ≠ 0

b) Find attached the solution

(c) By technology,

p - value = 0.4437

Hence, the p-value is 0.4437

8 0

2 years ago

A student estimates the weight of astronauts on the moon by multiplying their weight by the decimal 0.16666....what fraction can

Elden [556K]

Let $x = 1.66666...$ ....(1)

Multiply both sides of equation (1) by 10.

$10x = 1.666666....$ .... (2)

Multiply both sides of equation (1) by 100.

$100x = 16.66666....$ ... (3)

Subtract equation (2) from equation (3)

$100x - 10x = 16.66666...- 1.66666...$

$90x = 15$

$x= \frac{15}{90} = \frac{1}{6}$

Hence, the required fraction form is $\frac{1}{6}$ .... Answer.

3 0

2 years ago

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Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly s

kifflom [539]

Answer:

The expected number of tests, E(X) = 6.00

Step-by-step explanation:

Let us denote the number of tests required by X.

In the case of 5 individuals, the possible value of x are 1, if no one has the disease, and 6, if at least one person has the disease.

To find the probability that no one has the disease, we will consider the fact that the selection is independent. Thus, only one test is necessary.

Case 1: P(X=1) = [P (not infected)]⁵

= (0.15 - 0.1)⁵

P(X=1) = 3.125*10⁻⁷

Case 2: P(X=6) = 1- P(X=1)

= 1 - (1 - 0.1)⁵

P(X=6) = (1 - 3.125*10⁻⁷) = 0.999999

P(X=6) = 1.0

We can then use the previously determined values to compute the expected number of tests.

E(X) = ∑x.P(X=x)

= (1).(3.125*10⁻⁷) + 6.(1.0)

E(X) = E(X) = 6.00

Therefore, the expected number of tests, E(X) = 6.00

3 0

2 years ago

What is the recursive formula for this arithmetic sequence? -4, 3, 10, 17, ...

MatroZZZ [7]

5 0

2 years ago

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Find the sine function that is represented in the graph.

meriva

Answer:

Choice D). $f(x)=20\sin(4x)$ is correct.

Step-by-step explanation:

Given function graph is sinusoidal so let's compare with formula $f(x)=A\sin(Bx-C)+D$

We know that amplitude is the height from the center line to the peak (or to the trough). From graph we can see that height from the center line to the peak is 20

So amplitude A=20

In that formula, period is given by $\frac{2\pi}{B}$

From graph we see that period is $\frac{\pi}{2}$

So both must be equal

$\frac{2\pi}{B}=\frac{\pi}{2}$

$\frac{2}{B}=\frac{1}{2}$

cross multiplying them gives

B=4

Clearly there is no shift so C and D are 0

Now plug these values into formula $f(x)=A\sin(Bx-C)+D$

$f(x)=20\sin(4x-0)+0$

$f(x)=20\sin(4x)$

Hence choice D is correct.

6 0

2 years ago