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2 years ago

What is the absolute value of the complex number -4-√2i?

Mathematics

2 answers:

Leni [432]2 years ago

8 0

Answer-

The absolute value of the complex number is $3\sqrt2$

Solution-

The given complex number is,

$=-4-\sqrt2i$

The absolute value or modulus of a complex number a+bi, is defined as the distance between the origin (0,0) and the point (a,b) in the complex plane.

Its value is calculated by,

$|a+bi|=\sqrt{a^2+b^2}$

So,

$|-4-\sqrt2i|\\\\=\sqrt{(-4)^2+(-\sqrt2)^2}\\\\=\sqrt{16+2}\\\\=\sqrt{18}\\\\=3\sqrt2$

nataly862011 [7]2 years ago

4 0

Hello :
| -4-√2i | = √((-4)² +(-√2)²) =√(16+2) =√18 = √(9×2) = √9 × √2 = 3√2.. (answer B)

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