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astra-53 [7]
1 year ago
15

A fox sees a rabbit 35 feet away and starts chasing it. As soon as the fox starts moving the rabbit sees it and starts running a

way at a speed of 40 feet per second. What should the fox's speed be to catch up to the rabbit?
Mathematics
1 answer:
Artemon [7]1 year ago
4 0

The speed of the fox should be greater than the rabbit's speed in other to catch up, Hence, the speed of the fox must be 35/t + 40

The distance between the rabbit and fox, d = 35 feets

The rabbit's speed = 40 feets per second

Fox's speed = F

In other to obtain a specific speed for the fox, the time at which the fox is required to catch up with the rabbit should be given.

Let the time = t

Recall :

Speed = distance / time

Distance = speed × time

Rabbit's distance from fox after time t will be :

35 + (40 × t) = 35+40t

Fox's distance after time, t = fox speed × t = F × t

In other to catch up ; both fox and rabbit must be at the same distance ;

Rabbit's distance at time t = Fox's distance at time t

35+40t = Ft

To solve for F which is the fox's speed:

Divide both sides by t

(35+40t) / t = Ft/t

35/t + 40 = F

Hence, the fox' s speed must be : 35/t + 40

To obtain the exact speed of the fox, we must be given a specific time value.

Learn more : brainly.com/question/18112348

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91,000

Step-by-step explanation:

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5 hours + 4 hours = 9 hours
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A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
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Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

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<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

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1 year ago
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How many liters of wine can be held in a wine barrel whose capacity is 28.0 gal? 1 gal = 4 qt = 3.7854 l?
wel

Answer:

105.9912 liters of wine can be held in a wine barrel whose capacity is 28.0 gal.

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

Let x be the liters of wine can be held in a wine barrel whose capacity is 28.0 gal.

Given that:

1 gal = 3.7854 l

then

by definition of proportions;

\frac{1}{3.7854} =\frac{28}{x}

By cross multiply we get;

x = 28 \times 3.7854 = 105.9912 liters

Therefore, 105.9912 liters of wine can be held in a wine barrel whose capacity is 28.0 gal.

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Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water’s edge. The equation of her
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For this problem, we plug in the <em>numbers for t</em> and the <em>appropriate letters for e</em> to the equation <em>e = 300 - 10t</em>.

a) a = 300 - 10(-2)

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But, this is not a viable point because when t≤0, she doesn't move anywhere, thus, should consistently be 300 ft.

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c) c = 300 - 10(30)

simplify: c = 300 - 300

simplify: c = 0 ft.

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