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zzz [600]
2 years ago
11

Triangle L M N is shown. Angle L M N is a right angle. Angles N L M and L M N are 45 degrees. The length of L N is x. Which stat

ements are true regarding triangle LMN? Check all that apply. NM = x NM = LM = x StartRoot 2 EndRoot tan(45°) = StartFraction StartRoot 2 EndRoot Over 2 EndFraction tan(45°) = 1
Mathematics
2 answers:
shusha [124]2 years ago
8 0

Answer:

first , second , fourth

Step-by-step explanation:

Solnce55 [7]2 years ago
7 0

Answer:

A.) NM= x

C.) LM = x√2

E.) tan (45°) = 1

Step-by-step explanation:

If the legs are both x, then the hypotenuse is equal to x\sqrt{2

Therefore, LM= x\sqrt{2 is correct and MN= x

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Answer:

How many standard deviations above the mean is 14,500 hours? 1.25 1.5 2.5 Using the standard normal table, the probability that Seth's light bulb will last no more than 14,500 (P(z ≤ 1.25)) hours is about ✔ 89% .

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1 year ago
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The electric potential in a circuit is given by
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A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

8 0
2 years ago
The scale of map is 4cm: 1km, the simplest possible ratio is a. 1cm: 250m b. 3cm: 560m c. 2cm: 340m
Zolol [24]

Answer:

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Of the bundles delivered daily to the store, 1/3
Triss [41]

Answer:

x=9

Step-by-step explanation:

Let total bundle=x

Morning edition of the daily sun=1/3x

=x/3

Afternoon edition of the daily sun=2

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Cross product

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3 0
2 years ago
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