Answer:
Option A.
Step-by-step explanation:
The given expression is
![\dfrac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D)
where, 
.
We need to find the expression which is equivalent to the given expression.
The given expression can be rewritten as
![[\because \sqrt[n]{x}=x^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
![[\because (a^m)^n=a^{mn}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%5Em%29%5En%3Da%5E%7Bmn%7D%5D)
![[\because a^{-n}=\dfrac{1}{a^n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7B-n%7D%3D%5Cdfrac%7B1%7D%7Ba%5En%7D%5D)
Therefore, the correct option is A.
Given that you did not include the diagram showing the circle, the tangent line and the points Q, R, and S, I am going to give you the explanation to answer the question.
1) The tangent lines to a circle form a 90° angle with the radius at the point of intersection.
2) Therefore, if the point of intersection of the tangent line and the circle is named R, and the points S and Q are one the center of the circle and the other is on the line RQ, then you know that the segment SR is a radius and the line RQ is the tangent, which means that they are perpendicular, i.e. the angle QRS is measures 90°.
In this case the answer is m angle QRS = 90°.
3) Otherwise the angle is different to 90° and you need to observe the figure to conclude whether it is greater than 90°, less than 90° or there is not enough information.
Answer:
A. Constant of proportionality : Yes
B. Origin : No.
C. Inverse : No.
D. Rise per run : Yes
E. Unit rate : Yes.
Step-by-step explanation:
We have to choose yes or no to tell whether each item in the given options is equivalent to the slope in a proportional relationship.
A. Constant of proportionality: Yes
B. Origin: No.
C. Inverse: No.
D. Rise per run: Yes
E. Unit rate: Yes.
The constant of proportionality, the rise per run and the unit rate are equivalent to slope in a proportional relationship. (Answer)
Answer:
He set the compass on a, with the width slightly wider than the distance to o and drew an arc above and below o. He then set the compass on b, without changing the width on the compass and did the same thing. True
He drew a line through where the arc pairs intersected and then labeled the points where this line crossed the top and bottom of the original circle. True
He set the compass on o, with the width slightly wider than the distance to b, and he drew a slightly larger circle around the original circle. False
He used the points that were marked along the circumference of the original circle as the vertices for the square. True
Step-by-step explanation:
Performance matters test perhaps?
Answer: The comparison is mentioned below.
Step-by-step explanation:
A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally.
Therefore its slope = length of the equipment vertically / length of equipment horizontally
= 6/4 = 3/2 = 1.5
And, A piece of climbing equipment at a gym is 10 feet high and extends 6 feet horizontally.
Therefore slope, 
= 10/6 = 5/3=1.67 (approx)
Since, <
Thus the slope of equipment first is less than slope of second equipment.
