Yes. x=3 and y =9 are the solutions.
Because if you change x=3 and y =9 ,you will have
3+2* 9 =21
3+18 =21
21 =21 (true)
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.
She earned $3 more per hour for gardening than for office work.
Answer:
7.24pm
Step-by-step explanation:
196+50=3.9h
0.9h=0.9x60mnt=54mnt
3.9h=3h 54mnt
3:30pm+3h 54mnt
3:30pm+3h 54mnt=7.2pm
Answer:
29.15 km
Step-by-step explanation:
Given;
George walks; 25km west and then 15 km south
Resolving the directions to x and y axis;
North and South represent positive and negative y axis.
East and West represent positive and negative x axis respectively.
25km west
Rx = -25 km
15 km south
Ry = -15 km
The resultant displacement from the house is;
R = √(Rx^2 + Ry^2)
Substituting the values;
R = √((-15)^2 + (-25)^2)
R = √(225+625)
R = √(850)
R = 29.15 km
Therefore, he is 29.15 km from house