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almond37 [142]
2 years ago
10

A milestone occurring in which of these increments of time will be the farthest to the right on a timeline? A. 10 months B. 90 d

ays C. 8 years D. 16 weeks​
Mathematics
1 answer:
Naya [18.7K]2 years ago
6 0

Answer:

Step-by-step explanation:

16

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Mia has 1/2 of a pizza. She divides it equally among 4 people. Which model shows the fraction of a whole pizza each person gets
Llana [10]

Each person gets \frac{1}{8} of whole pizza

<em><u>Solution:</u></em>

Given that Mia has \frac{1}{2} of a pizza

She divides it equally among 4 people

<em><u>To find: Fraction of a whole pizza each person gets</u></em>

From statement,

\frac{1}{2} of pizza is divided equally among 4 people

Therefore, to find the fraction of whole pizza each person gets, we can divide the \frac{1}{2} by 4 people

\text{fraction each person gets } = \frac{\frac{1}{2}}{4}\\\\\text{fraction each person gets } = \frac{1}{2} \times \frac{1}{4}\\\\\text{fraction each person gets } = \frac{1}{8}

Thus each person gets \frac{1}{8} of whole pizza

3 0
2 years ago
Paula has a dog that weighs 3 times as much as Carla's dog
ivanzaharov [21]

Answer:

The weight of Paula's dog is 36 pounds.

Step-by-step explanation:

SO we would draw one box for the weight of Carla's dog. Then we would draw 3 boxes for the weight of Paula's dog.

To find how much does Paula's dog weigh we divide the total weight of the dogs by the total number of boxes.

So then you would calculate 48 divided by 4.

The weight of Carla's dog is 12 pounds.

Therefore the weight of Paula's dog is 3x12=3x10+3x2=30+6=36 pounds.

4 0
1 year ago
Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o
AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that \mu = 490, \sigma = \sqrt{400} = 20

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{500 - 490}{20}

Z = 0.5

Z = 0.5 has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

4 0
1 year ago
If y varies directly as x, and y is 400 when x is r and y is r when x is 4, what is the numeric constant of variation in this
otez555 [7]

Answer:

10

Step-by-step explanation:

If there is a direct relation between two variables x and y then it can be represented as

y = kx ,

where y is dependent variable

x is  independent variable

k is constant of variation

_____________________________

First condition

y = 400

x = r

using y = kx then relationship will be

400 = kr

finding k here

k = 400/r

Second condition

y = r

x = 4

using y = kx then relationship will be

r = 4k

finding k

k = r/4

since  in both condition equation is same

thus, value of k will also be same

thus,

400/r = r/4

=> 400*4 = r*r

=> 1600 = r^2

\sqrt{r^{2} }  = \sqrt{1600} \\r = 40

Thus, 40 is the value of r

k = r/4 = 40/4 = 10

Thus, constant of variation is 10 which is correct choice.

To cross validate

k = 400/r = 400/40 = 10

7 0
1 year ago
Read 2 more answers
**WARNING** IF YOU ANSWER THIS QUESTION INCORRECTLY OR TRY TO ANSWER WITH FOOLISHNESS YOU WILL GET REPORTED
frozen [14]

The solution is attached as a word file.

Download doc
3 0
2 years ago
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