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OLga [1]
2 years ago
10

A construction crew is lengthening a road. The road started with a length of 54 miles, and the crew is adding 3 miles to the roa

d each day. Let L represent the total length of the road (in miles), and let D represent the number of days the crew has worked. Write an equation relating L to D . Then use this equation to find the total length of the road after the crew has worked 39 days.
Mathematics
1 answer:
patriot [66]2 years ago
6 0
53+3(D) = L

53 + 3(38) =L

53 +114 = L

167=L
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As the weight of purchased items increases, the shipping charges increase, as shown in the table below. Weight, in oz Total Ship
ankoles [38]
The correct answer is beginning at 5 ounces, the graph is discontinuous every 5th integer of the domain.

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6 0
2 years ago
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Order the set (-5,3,2,-7) from greatest to least
STatiana [176]
3,2,-5,-7 that is the order it should be in
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According to a 2013 study by the Pew Research Center, 15% of adults in the United States do not use the Internet (Pew Research C
Pavel [41]

Answer:

a) For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

b) P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969

c) P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298

d) P(X \geq 1)= 1-P(X

And using the result from part a we got:

P(X \geq 1)= 1-P(X

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n p)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

Part b

For this case we want this probability:

P(X=0)

And replacing we got:

P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969

Part c

For this case we want this probability:

P(X=3)

And replacing we got:

P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298

Part d

For this cae we want thi probability:

P(X \geq 1)

And we can use the complment rule and we got:

P(X \geq 1)= 1-P(X

And using the result from part a we got:

P(X \geq 1)= 1-P(X

4 0
2 years ago
How many times greater is the value of the digit 8 in 82.77 than the value of the digit 8 in 20.18
Kitty [74]

Answer:

Option 3. 1,000 times

Step-by-step explanation:

we know that

The value of digit 8 in 82.77 is equal to 80

The value of digit 8 in 20.18 is 0.08

so

Divide 80 by 0.08

80/0.08=1,000 times

3 0
2 years ago
Each month Liz pays $35 to her phone company just to use the phone. Each text she sends costs her an additional $0.05. In March
olchik [2.2K]
First let's set up an equation: 35+0.05t. 
35 is the phone rate per month plus the number of texts (t) times 0.05 (cost of 1 text)

Now we can find the amount of texts she sent each month.

March
 35+0.05t=72.60
-35               -35
0.05t=37.60
------   -------
0.05    0.05
t=752

April
 35+0.05t=65.85
-35            -35
0.05t=30.85
------   -------
0.05    0.05
t=617

She sent 752 texts in March and 617 texts in April.


7 0
2 years ago
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