We are given with
F = 1000
b = 22.50
P = 100.8
We use the formula to get the coupon rate
b = Fib
Substituting the given values
22.50 = 1000 ib
ib = 0.0255 or 2.25%
The coupon rate is 2.25%
<span>Nevermind the answer was x=1 and x=2. If anyone is wondering how to do it you can put the denominator in desmos and where the 2 points hit the x axis is your answer.</span>
Answer:
7 pages
Step-by-step explanation:
Given the total number of pages in the book are 16
The number of pages esteban already read are 9
Let the number of pages left out to read be x
Total number of pages = number of pages read + number of pages to be read
16=9+x
x=16-9
x=7 pages
Therefore There are 7 pages left out to be read.
In a large population, 61% of the people are vaccinated, meaning there are 39% who are not. The problem asks for the probability that out of the 4 randomly selected people, at least one of them has been vaccinated. Therefore, we need to add all the possibilities that there could be one, two, three or four randomly selected persons who were vaccinated.
For only one person, we use P(1), same reasoning should hold for other subscripts.
P(1) = (61/100)(39/100)(39/100)(39/100) = 0.03618459
P(2) = (61/100)(61/100)(39/100)(39/100) = 0.05659641
P(3) = (61/100)(61/100)(61/100)(39/100) = 0.08852259
P(4) = (61/100)(61/100)(61/100)(61/100) = 0.13845841
Adding these probabilities, we have 0.319761. Therefore the probability of at least one person has been vaccinated out of 4 persons randomly selected is 0.32 or 32%, rounded off to the nearest hundredths.
