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just olya [345]
2 years ago
13

A man is on a 1/4 on a bridge. A train is coming the same direction he is going. The man can run across the bridge in the same d

irection and make in barely in time. He can also run backwards towards the train and also barely make it. How fast is the train going relative to the man.

Mathematics
1 answer:
Anon25 [30]2 years ago
4 0

Answer:

The train is twice fast going relative to the man.

Step-by-step explanation:

Consider the provided information.

Let the distance between the train and beginning of bridge is x and length of bridge is y.

A man is on a 1/4 on a bridge. Thus, the 1/4 of y is y/4.

The train is going x distance in time man runs y/4 distance.

Also if the train is going x + y in time man runs the distance 3y/4.

For better understanding refer the figure 1:

So, if train goes x+y-x distance in time man covers the distance 3y/4 - y/4

Now solve 3y/4 - y/4  = 2y/4

The train covers y distance in the time man runs 2y/4 = y/2

That means train covers 2 times of the distance cover by the man or the train goes twice as fast as man.

Hence, train is twice fast going relative to the man.

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First you must know that there are 16 ounces in 1 pound so the amount of ounces in 5 pounds would be 80 ounces so first you would take out one ounce for the $0.35 and would then have 79 ounces. After that you would multiply 79 by .10 to get 7.90 then add the .35 to that to get

8.25. So the answer is c.

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Half the product of two numbers a and b, added to thrice a third number c
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8 0
1 year ago
If e = 9 cm and f = 40 cm, what is the length of g?
rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.  

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

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2 years ago
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