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Paha777 [63]
1 year ago
9

Without any equipment you can see stars that are 2,800,000 light years away. By looking at through a small telescope you can see

the stars that are 3,112,000,000 light years away. Approximately how many times as far can you see using a small telescope as without any equipment.
A. 1x 10^2
B. 3x 10^2
C. 1x 10^3
D. 3x 10^3
Mathematics
1 answer:
Stells [14]1 year ago
4 0

Answer:

hi

Step-by-step explanation:

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Callie was billed $416.48 for car repairs. She will pay the service center in 4 equal monthly installments from her bank account
Sav [38]

Answer:

her monthly payments will be $104.12

Step-by-step explanation:

she will pay off the entire bill after 4 months

416.48 - 104.12n = 0

-104.12n = -416.48

n = 4

6 0
2 years ago
Read 2 more answers
Sarah and her friends are going blueberry picking. Sarah picks $b$ blueberries. Michael picks $3$ more than half as many as Sara
yKpoI14uk [10]
The correct answer is b=3+1/2 divided by 5+3 after that +10-3*5*3 . add the answers up and thats the solution
6 0
1 year ago
There is a point $A$ with positive coordinates such that the sum of the coordinates of $A$ is $14$. If the $x$-coordinate of $A$
ch4aika [34]

Answer:

  5

Step-by-step explanation:

<u>Given</u>:

  A = (a, 14-a)

  P = (3a, a^2 +13a -11)

  the slope of AP is 7

  a > 0

<u>Find</u>:

  a

<u>Solution</u>:

The slope of AP is ...

  m = (Py -Ay)/(Px -Ax)

  7 = (a^2 +13a -11 -(14 -a))/(3a -a)

  14a = a^2 +14a -25

  25 = a^2

  a = √25 = 5 . . . . . the positive solution

The value of 'a' is 5.

_____

<em>Check</em>

The point A is (a, 14-a) = (5, 9).

The point P is (3a, a^2 +13a -11) = (15, 79)

The slope of AP is (79 -9)/(15 -5) = 70/10 = 7.

6 0
1 year ago
The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find
fenix001 [56]

Answer:

y2 = (6x + 7)/36 + (Dx + E)e^x

Step-by-step explanation:

The method of reduction of order is applicable for second-order differential equations.

For a known solution y1 of a 2nd order differential equation, this method assumes a second solution in the form Uy1 which satisfies the said differential equation. It then assumes a reduced order for U'' (w' = U'').

The differential equation becomes easy to solve, and all that is left are integration and substitutions.

Check attachments for the solution to this problem.

6 0
1 year ago
Three out of seven students in the cafeteria line are chosen to answer survey questions. How many different combinations of thre
Andreyy89

Answer:

The number of different combinations of three students that are possible is 35.

Step-by-step explanation:

Given that three out of seven students in the cafeteria line are chosen to answer a survey question.

The number of different combinations of three students that are possible is given as:

7C3 (read as 7 Combination 3)

xCy (x Combination y) is defines as

x!/(x-y)!y!

Where x! is read as x - factorial or factorial-x, and is defined as

x(x-1)(x-2)(x-3)...2×1.

Now,

7C3 = 7!/(7 - 3)!3!

= 7!/4!3!

= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)

= (7×6×5)/(3×2×1)

= 7×5

= 35

Therefore, the number of different combinations of three students that are possible is 35.

3 0
2 years ago
Read 2 more answers
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