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Elina [12.6K]
2 years ago
7

Identifying a Valid Sample Natasha wants to find out if the neighborhood supports lowering the speed limit on the street in fron

t of her school. Which is a valid sample for the survey? students in Natasha’s social studies class parents who live in a town 15 miles away from Natasha’s school the first 5 drivers who drive past Natasha’s school one morning thirty residentsIdentifying a Valid Sample Natasha wants to find out if the neighborhood supports lowering the speed limit on the street in front of her school. Which is a valid sample for the survey?
A. students in Natasha’s social studies class parents who live in a town 15 miles
B.away from Natasha’s school the first 5 drivers who drive past Natasha’s C.school one morning thirty residents who live within a 2-miles radius of D.Natasha’s school who live within a 2-miles radius of Natasha’s school
Mathematics
2 answers:
nekit [7.7K]2 years ago
7 0

D - Thirty Residents Who Live Within a 2-Miles Radius Of Natasha’s School

blsea [12.9K]2 years ago
3 0

Answer:

thirty residents who live within a 2-miles radius of Natasha’s school

Step-by-step explanation:

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Find -34 + 15 - 29 - (-3)
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Answer:

-45

Step-by-step explanation:

-34+15=-19

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-19 + -26 = -45

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The value of good wine increases with age. Thus, if you are a wine dealer, you have the problem of deciding whether to sell your
Katyanochek1 [597]

Answer: 64 years

Step-by-step explanation:

Let assume the dealer sold the bottle now for $P, then invested that money at 5% interest. The return would be:

R1 = P(1.05)^t,

This means that after t years, the dealer would have the total amount of:

$P×1.05^t.

If the dealer prefer to wait for t years from now to sell the bottle of wine, then he will get the return of:

R2 = $P(1 + 20).

The value of t which will make both returns equal, will be;

R1 = R2.

P×1.05^t = P(1+20)

P will cancel out

1.05^t = 21

Log both sides

Log1.05^t = Log21

tLog1.05 = Log21

t = Log21/Log1.05

t = 64 years

The best time to sell the wine is therefore 64years from now.

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2 years ago
HELP! A daycare purchases two type of snacks, granola bars and fruit rolls. One week, they purchase 10 packs of granola bars and
ch4aika [34]
10x+6y=152
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There are 8 granola bars in a pack and 12 fruit rolls in a pack
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Jocelyn is considering taking out one of the two following loans. Loan H is a three-year loan with a principal of $5,650 and an
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Mopeds (small motorcycles with an engine capacity below 50 cm3) are very popular in Europe because of their mobility, ease of op
Mashcka [7]

Answer:

a) P(X<50)=0.9827

b) P(X>47)=0.4321

c) P(-1.5<z<1.5)=0.8664

Step-by-step explanation:

We will calculate the probability based on a random sample of one moped out of the population, normally distributed with mean 46.7 and standard deviation 1.75.

a) This means we have to calculate P(x<50).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

z=\dfrac{X-\mu}{\sigma}=\dfrac{50-46.7}{1.75}=\dfrac{3.7}{1.75}=2.114\\\\\\P(X

b) We have to calculatee P(x>47).

We will calculate the z-score and then calculate the probability accordign to the standard normal distribution:

z=\dfrac{X-\mu}{\sigma}=\dfrac{47-46.7}{1.75}=\dfrac{0.3}{1.75}=0.171\\\\\\P(X>47)=P(z>0.171)=0.4321

c) If the value differs 1.5 standard deviations from the mean value, we have a z-score of z=1.5

z=\dfrac{(\mu+1.5\sigma)-\mu}{\sigma}=\dfrac{1.5\sigma}{\sigma}=1.5

So the probability that maximum speed differs from the mean value by at most 1.5 standard deviations is P(-1.5<z<1.5):

P(-1.5

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2 years ago
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