Answer:
P(working product) = .99*.99*.96*.96 = .0.903
Step-by-step explanation:
For the product to work, all four probabilities must come to pass, so that
P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)
where
P(Part-1) = 0.96
P(Part-2) = 0.96
P(Part-3) = 0.99
P(Part-4) = 0.99
As all parts are independent, so the formula is P(A∩B) = P(A)*P(B)
P (Working Product) = P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)
P (Working Product) = 0.96*0.96*0.96*0.99*0.99
P(Working Product) = 0.903
We may answer the question above by dividing the expression y² - 10x + 24 with the given factor, y - 4. The division would give an answer of y - 6. Thus,
<span>y² - 10x + 24 = (y - 4)(y - 6)
The answer is the fourth choice, y - 6.</span>
To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows;
From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score
(x-μ)/σ
we shall have:
(x-5000)/50=-2.57
solving for x we get:
x-5000=-128.5
x=-128.5+5000
x=4871.50
Answer:
76% of X= 9.12. X= 12 gram. Therefore weight of the sample is 12 gram.
Step-by-step explanation:
i hope it's help you
Using normal distribution
critical probability
critical value for the critical probability is CV = 1.96
standard error
margin of error = CV*SE = 1.96 * 0.5 = 0.98
95% confidence interval is between μ + 0.98 and <span>μ - 0.98, which is (19.62, 21.58)</span>
