Answer:
its b. cuz got the friggen question wrong when i did it. >:(
If 9 of the sparrows is 45% of the birds in the backyard, 9/x = 45/100.
Cross multiply to get 9 * 100 = 45x; simplified is 900 = 45x or 20.
This means that there are 20 birds in the backyard. You can check this by dividing 9/20 which equals 45%
Answer:
d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.
Step-by-step explanation:
Confidence interval:
x% confidence
Of a sample
Between a and b.
Interpretation: We are x% sure(or there is a x% probability/chance) that the population mean is between a and b.
In this question:
I suppose(due to the options) there was a small typing mistake, and we have a 98% confidence interval between 0.56 and 0.62.
Interpreation: We are 98% sure, or there is a 98% chance, that the true population proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. Option d.
To answer the question, all the statements must be analyzed with the data presented in the table.
From the table we get that the team played 16 games at home and 11 games away from home.
In total, they played 27 games.
Of the 16 games at home, the team won 6. Then, the proportion of games won at home is:
6/16 = 0.375.
Of the 11 games away from home, the team won 3. Then the proportion of games won away from home is:
3/11 = 0.272.
0.375 is not twice 0.272.
Then the first statement is incorrect.
The ratio of games won at home is 6/16 = 3/8. Therefore, the second statement is incorrect. The team does not win 3/5 of the games at home.
The total number of games won is 9 and the total number of games is 27.
So, the third statement is incorrect. The team does not win half of the games.
The fourth statement is true. The team played 27 games
The fifth statement is false because the team won more than 6 games. They won 3 games away from home and 6 games at home
Finally, the sixth statement is correct, because the team lost 10 games at home and 8 away from home. However, the PERCENTAGE of games lost away from home is greater than the PERCENTAGE of games lost at home. Therefore, it is more likely that the team loses when playing away from home.
