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fgiga [73]
2 years ago
11

Two boys play basketball in the following way. They take turns shooting and stop when a basket is made. Player A goes first with

a probability p1 of making a basket on any throw. Player B, who shoots second, has probability 2 p of making a basket. The outcomes of the successive trials are assumed to be independent. (a) Find the probability mass function for the total number of attempts. (b) What is the probability that player A wins
Mathematics
1 answer:
Softa [21]2 years ago
6 0

Answer:

P(A) = p1 (1 − q1q2)

Step-by-step explanation:

Let A = player A wins,

then  P(A) = p1 + (1 − p1)(1 − p2)P(A)

⇒ P(A) = p1 (1 − q1q2)

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A farmer sells 6.5 kilograms of pears and apples at the farmer's market. 3/4 of this weight is pears, and the rest is apples. Ho
Jet001 [13]

Answer:

1.625 kilograms

Step-by-step explanation:

Since total weight of pears and apples is 6.5 kilograms and 3/4 of this weight is pears, the weight of the pears is

→ 6.5 x 3/4 = 4.875 kilograms

Since the weight of the pears is 4.875, we can subtract it from the total weight to find the weight of the apples

→ 6.5 - 4.875 = 1.625 kilograms

8 0
2 years ago
Read 2 more answers
Subtract 25.45 from 51.82. Give your answer to 2 decimal places.
Usimov [2.4K]

Answer:

Answer is, 26.4

Step-by-step explanation:

By subtracting 51.82 by 26.37, you're left with a total of 26.37, and by rounding that to the tenths place, you get 26.4

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2 years ago
Sarah's dad bought her a scooter that cost $89.95. He figures he can spend up to $30.05 on a helmet before he spends too much mo
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1 year ago
You have found a home that you are interested in purchasing. Instead of a conventional loan, you agree to pay the premium for th
Elena-2011 [213]
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Down payment is 5% of the amount listed
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5 0
2 years ago
The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va
Firlakuza [10]

Answer:

1

  The  probability is  P(\= X < 33) = 0.8531

2

  The  probability is  P(\= X > 30) = 0.3520

Step-by-step explanation:

From the  question we are told that

     The population mean is  \mu =  28.29

      The standard deviation is \sigma  =  33.493

       The sample size is  n  = 56

Generally the standard error for the  sample  mean (\= x ) is mathematically evaluated as

        \sigma _{\=x} =  \frac{\sigma}{\sqrt{n} }

substituting values  

       \sigma _{\=x} =  \frac{33.493}{\sqrt{56} }

      \sigma _{\=x} = 4.48

Apply central limit theorem[CLT] we have  that

        P(\= X < 33) =  [z <  \frac{33 -  \mu }{\sigma_{\= x}} ]

substituting values

       P(\= X < 33) =  [z <  \frac{33 -  28.29 }{4.48} ]

       P(\= X < 33) =  [z <  1.05 ]

From the z-table  we have that  

       P(\= X < 33) = 0.8531

For the second question

    Apply central limit theorem[CLT] we have  that

    P(\= X > 30 ) =  [z >  \frac{30 -  \mu }{\sigma_{\= x}} ]

substituting values

   P(\= X < 33) =  [z >  \frac{30 -  28.29 }{4.48} ]

From the z-table  we have that  

     P(\= X < 30) = 0.6480

Thus  

     P(\= X > 30) = 1- P(\= X < 30) = 1- 0.6480

     P(\= X > 30) = 0.3520

3 0
2 years ago
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