520*.04=20.8, or closer to 21 spam emails.
Answer:
Step-by-step explanation:
Since we are not told what to find, we can as well find the time taken by the rocket to reach its maximum height as shown
The rocket reaches its maximum height when the velocity is zero
v = dh/dt
v = -32t+64
Since v = 0 at maximum height
0 = -32t+64
32t = 64
t = 64/32
t = 2secs
Hence the rocket reaches the maximum height after 2secs
P(82 - q < x < 82 + q) = 0.44
P(x < 82 + q) - P(82 - q) = 0.44
P(z < (82 + q - 82)/7.4 - P(z < (82 - q - 82)/7.4) = 0.44
P(z < q/7.4) - P(z < -q/7.4) = 0.44
P(z < q/7.4) - (1 - P(z < q/7.4) = 0.44
P(z < q/7.4) - 1 + P(z < q/7.4) = 0.44
2P(z < q/7.4) - 1 = 0.44
2P(z < q/7.4) = 1.44
P(z < q/7.4) = 0.72
P(z < q/7.4) = P(z < 0.583)
q/7.4 = 0.583
q = 0.583 x 7.4 = 4.31
Answer:
fifty five thousand four hundred and twenty six.
Step-by-step explanation:
Answer:
9.48*
Step-by-step explanation:
This is a right triangle. The formula for solving the Hypotenuse, or the longest side of the right triangle is A^2 + B^2 = C^2. If we put the numbers from the problem into the formula this is what we get :
3^2 + 9^2 = C^2
9 + 81 = C^2
90 = C^2
9.48 = C
* This is rounded, the exact number is closer to 9.486832980505138. Your class should tell you what to round to.
