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2 years ago

Gina has 5 2/6 feet of silver ribbon and 2 4/6 of gold ribbon. how much more silver ribbon does gina have than golden ribbon?

2 answers:

8 0

To answer the question above, we are simply to subtract the length of the gold ribbon which is 2 4/6 ft from the length of the silver ribbon, 5 2/6 feet. Mathematically,
5 2/6 feet - 2 4/6 feet = 8/3 feet
Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon.

lions [1.4K]2 years ago

5 0

In order to answer the question, we just have to subtract the length of the gold ribbon which from the length of the silver ribbon. We do it as follows:

5 2/6 feet - 2 4/6 feet = 8/3 feet

Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon. Hope this answers the question. Have a nice day.

You might be interested in

A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an

Amanda [17]

Answer: $\mu_x=18\text{ hours}$

$\sigma_x=4\text{ hours}$

Step-by-step explanation:

We know that mean and standard deviation of sampling distribution is given by :-

$\mu_x=\mu$

$\sigma_x=\dfrac{\sigma}{\sqrt{n}}$

, where $\mu$ = population mean

$\sigma$ =Population standard deviation.

n= sample size .

In the given situation, we have

$\mu=18\text{ hours}$

$\sigma=6\text{ hours}$

n= 2

Then, the expected mean and the standard deviation of the sampling distribution will be :_

$\mu_x=\mu=18\text{ hours}$

$\sigma_x=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{2}}=4.24264068712\approx4$ [Rounded to the nearest whole number]

Hence, the the expected mean and the standard deviation of the sampling distribution :

$\mu_x=18\text{ hours}$

$\sigma_x=4\text{ hours}$

7 0

2 years ago

The volume of a sphere is 5,000pi m3. What is the surface area of the sphere to the nearest square meter?

tia_tia [17]

Surface area of a sphere = 4πr2
the volume of a sphere= 43πr3
so 5000π=4/3πr3
> r^3 = 5000 x 3 / 4 =>
r^3 = 3750
taking cube root on both sides
r=15.53616
hope it helps

5 0

2 years ago

Read 2 more answers

A basketball is rolling with a velocity of 0.5 meters/second relative to the ground and due north. A tennis ball is rolling with

RSB [31]

Ok so let me help you like this: We need to understand first that The basketball has a higher speed, that means that the tennis ball will never catch up. so what we need to use is the formula
Vr=Vb--Vt
=0.5-0.25=0.25
So the speed is 0.25m/s
Hope this is useful

5 0

2 years ago

A marketing firm wants to estimate how much root beer the average teenager drinks per year. A previous study found a standard de

Verdich [7]

Answer:

At least 832 teenargers must be interviewed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How many teenagers must the firm interview in order to have a margin of error of at most 0.1 liter when constructing a 99% confidence interval

At least n teenargers must be interviewed.

n is found when M = 0.1.

We have that $\sigma = 1.12$

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 2.575*\frac{1.12}{\sqrt{n}}$

$0.1\sqrt{n} = 2.575*1.12$

$\sqrt{n} = \frac{2.575*1.12}{0.1}$

$(\sqrt{n})^{2} = (\frac{2.575*1.12}{0.1})^{2}$

$n = 831.7$

Rounding up

At least 832 teenargers must be interviewed.

4 0

2 years ago

The average time taken to complete an exam, X, follows a normal probability distribution with mean = 60 minutes and standard dev

k0ka [10]

Answer: b. 0.8413

Step-by-step explanation:

Given : The average time taken to complete an exam, X, follows a normal probability distribution with $\mu=60\text{ minutes}$ and $\sigma=30\text{ minutes}$ .

Then, the probability that a randomly chosen student will take more than 30 minutes to complete the exam will be :-

$P(x>30)=P(z>\dfrac{30-60}{30})\ \ [\because\ z=\dfrac{x-\mu}{\sigma} ]\\\\=P(z>-1)=P(z-z)=P(Z$

[using z-value table]

Hence, the probability that a randomly chosen student will take more than 30 minutes to complete the exam = 0.8413

3 0

2 years ago