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1 year ago

Gina has 5 2/6 feet of silver ribbon and 2 4/6 of gold ribbon. how much more silver ribbon does gina have than golden ribbon?

2 answers:

8 0

To answer the question above, we are simply to subtract the length of the gold ribbon which is 2 4/6 ft from the length of the silver ribbon, 5 2/6 feet. Mathematically,
5 2/6 feet - 2 4/6 feet = 8/3 feet
Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon.

lions [1.4K]1 year ago

5 0

In order to answer the question, we just have to subtract the length of the gold ribbon which from the length of the silver ribbon. We do it as follows:

5 2/6 feet - 2 4/6 feet = 8/3 feet

Therefore, Gina has 8/3 feet more of the silver ribbon than the golden ribbon. Hope this answers the question. Have a nice day.

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2 years ago

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FromTheMoon [43]

For this case what we must do is find a quadratic function that is already factored.
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2 years ago

Two tangents each intersect a circle at opposite

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Answer:

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Step-by-step explanation:

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A particle moves on the circle x2+y2=25 in the xy-plane for time t≥0. At the time when the particle is at the point (3,4), dx/dt

yaroslaw [1]

Answer:

$\displaystyle y'=-\frac{9}{2}$

Step-by-step explanation:

<u>Differentiation</u>

We have a relationship between x and y as follows:

$x^2+y^2=25$

Both variables depend on time t for t≥0.

Differentiating with respect to time:

$(x^2)'+(y^2)'=(25)'$

Applying the derivative of a power function:

$2xx'+2yy'=0$

Recall the derivative of a constant is 0.

Dividing by 2:

$xx'+yy'=0$

Solving for y':

$\displaystyle y'=-\frac{xx'}{y}$

At some specific time, we have:

x=3, y=4, dx/dt = x' = 6. Substituting:

$\displaystyle y'=-\frac{3\cdot 6}{4}$

Operating:

$\displaystyle y'=-\frac{18}{4}$

Simplifying:

$\mathbf{\displaystyle y'=-\frac{9}{2}}$

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1 year ago

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Hello here is a solution :
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