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Mars2501 [29]
2 years ago
5

Karson drove from his house to work at an average speed of 35 miles per hour.  The drive took him 20 minutes.  If the drive took

him 25 minutes and he used the same route in reverse, what was his average speed going home. (Hint: inversely proportional)​
Mathematics
1 answer:
Nastasia [14]2 years ago
3 0

Answer:

Karson's average speed on his way home was 28 miles per hour.

Step-by-step explanation:

Since Karson drove from his house to work at an average speed of 35 miles per hour, and the drive took him 20 minutes, if the drive took him 25 minutes and he used the same route in reverse, to determine what was his average speed going home, the following calculation must be performed:

60 = 35

20 = X

20 x 35/60 = X

700/60 = X

11.666 = X

25 = 11,666

60 = X

60 x 11.666 / 25 = X

27.99 = X

Therefore, Karson's average speed on his way home was 28 miles per hour.

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Salsk061 [2.6K]

Answer:

a) 1 tsp.

b) 1.5 tsp.

c) 2 tsp.

Step-by-step explanation:

Complete Correct Question

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog

- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

Solution

a) 18 kg adult dog

The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

9 kg dog weight = (1/2) tsp

18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.

b) 6 kg cat

The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

1 kg cat = (1/4) tsp

6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.

c) 18 kg pregnant dog

The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

4.5 kg dog weight = (1/2) tsp

18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.

Hope this Helps!!!

4 0
2 years ago
Read 2 more answers
Nine new employees, two of whom are married to each other, are to be assigned nine desks that are lined up in a row. If the assi
meriva

Answer:

The probability is 0.8

Step-by-step explanation:

The key to answering this question is considering the fact that the two married employees be treated as a single unit.

Now what this means is that we would be having 8 desks to assign.

Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!

Now, the number of ways the couple can interchange their desks is just 2 ways

Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)

The number of ways to assign desks among all six employees randomly is 9!

Thus, the probability that the couple will have adjacent desks would be ;

2(8!)/9! = 2/9

This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778

Which is 0.8 to the nearest tenth of a percent

4 0
2 years ago
A teacher gave a quiz to her class of 30 students. However, she misplaced one of the quizzes. The teacher calculated the mean of
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Answer:

B

Step-by-step explanation:

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2 years ago
How is quadrilateral ABCD related to quadrilateral A'B'C'D' shown below?
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What you put is correct. A’B’C’D’ is what would be shown if you rotate ABCD 90 degrees clockwise
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2 years ago
A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (80
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Answer:

\epsilon = 3.958\times 10^{-3}

Step-by-step explanation:

The Young's Module of Aluminium is E = 69\times 10^{9}\,Pa. The axial stress on the specimen is:

\sigma = \frac{F}{A_{t}}

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\sigma = 2.731\times 10^{8}\,Pa

The strain is derived of following expression:

\epsilon = \frac{\sigma}{E}

\epsilon = \frac{2.731\times 10^{8}\,Pa}{69\times 10^{9}\,Pa}

\epsilon = 3.958\times 10^{-3}

4 0
2 years ago
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