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daser333 [38]
2 years ago
9

Hannah factored the expression 24xy + 15y. Her work is shown below. 1. GCF (24xy, 15y) = 3y 2. 24xy/3 = 8xy, 15y/3 = 5y 3. 3(24x

y + 15y) What are the errors in Hannah's work? Check all that apply. She divided by 3 instead of the GCF. She found the wrong GCF. She divided wrongly. She didn't complete step 4 and use the distributive property to be sure the expressions are equivalent. She didn't undistribute the GCF from the original expression.
Mathematics
2 answers:
jek_recluse [69]2 years ago
7 0

Answer:

A, D and E is your answer

Good luck!! :) :p

murzikaleks [220]2 years ago
3 0

- She divided by 3 instead of the GCF.

- She didn’t complete step 4 and use the distributive property to be sure the expressions are equivalent.

- She didn’t undistribute the GCF from the original expression.

Explanation:

I just did it lol

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Take 8 times 7% and then take 8 time 15% add those numbers too $8 and you will find your answer. 7% = 7/100 and 15% = 15/100
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lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

\frac{2}{5} = \frac{x}{340,000}

Cross multiply it and solve for x

340000* 2 = 5x

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Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

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If f(x) = 1 – x, which value is equivalent to |f(i)|? options are:
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ZanzabumX [31]

Answer:

a) 22.94 psi

b) 5.93\times10^{-5}

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b) The probability that that the TPMS will trigger warning at 22.94 psi, given that tire pressure has a normal distribution with average of 31 psi and standard deviation of 2 psi

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where x = 22.94, \mu = 31, \sigma = 2

f(22.94)={\frac {1}{2 {\sqrt {2\pi }}}}e^{-{\frac {1}{2}}\left({\frac {22.94-31}{2 }}\right)^{2}}

f(22.94)=0.2e^{-8.12} = 5.93\times10^{-5}

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Scorpion4ik [409]

Answer:

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