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EastWind [94]
1 year ago
10

Select all polynomials that have (x-3)(x−3)left parenthesis, x, minus, 3, right parenthesis as a factor. Choose all answers that

apply: Choose all answers that apply: (Choice A) A A(x)=x^3-2x^2-4x+3A(x)=x 3 −2x 2 −4x+3A, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 2, x, squared, minus, 4, x, plus, 3 (Choice B) B B(x)=x^3+3x^2-2x-6B(x)=x 3 +3x 2 −2x−6B, left parenthesis, x, right parenthesis, equals, x, cubed, plus, 3, x, squared, minus, 2, x, minus, 6 (Choice C) C C(x)=x^4-2x^3-27C(x)=x 4 −2x 3 −27C, left parenthesis, x, right parenthesis, equals, x, start superscript, 4, end superscript, minus, 2, x, cubed, minus, 27 (Choice D) D D(x)=x^4-20x-21D(x)=x 4 −20x−21
Mathematics
1 answer:
iVinArrow [24]1 year ago
4 0

Answer:

  A, C, D

Step-by-step explanation:

One way to answer this question is to use synthetic division to find the remainder from division of the polynomial by (x-3). If the polynomial is written in Horner form, evaluating the polynomial for x=3 is substantially similar.

  A(x) = ((x -2)x -4)x +3

  A(3) = ((3 -2)3 -4)3 +3 = -3 +3 = 0 . . . . . has a factor of (x -3)

__

  B(x) = ((x +3)x -2)x -6

  B(3) = ((3 +3)3 -2)3 -6 = (16)3 -6 = 42 . . . (x -3) is not a factor

__

  C(x) = (x -2)x^3 -27

  C(3) = (3 -2)3^3 -27 = 0 . . . . . . . . . . . . . has a factor of (x -3)

__

  D(x) = (x^3 -20)x -21

  D(3) = (3^3 -20)3 -21 = (7)3 -21 = 0 . . . . has a factor of (x -3)

___

The polynomials of choice are A(x), C(x), and D(x).

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Triangle PQR with vertices P(3, −6), Q(6, −9), and R(−15, 3) is dilated by a scale factor of 3 to obtain triangle P′Q′R′. Which
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Answer:

Option C.

Step-by-step explanation:

The vertices of triangle PQR are P(3, −6), Q(6, −9), and R(−15, 3).

It is given that triangle PQR dilated by a scale factor of 3 to obtain triangle P′Q′R′.

We know that a figure and its image after dilation are similar. It means triangle PQR and triangle P′Q′R′

If a figure dilated by factor k about the origin then

(x,y)\rightarrow (kx,ky)

PQR dilated by a scale factor of 3, so

(x,y)\rightarrow (3x,3y)

Using this rule we get

P(3,-6)\rightarrow P'(3(3),3(-6))=P'(9,-18)

Q(6,-9)\rightarrow Q'(3(6),3(-9))=Q'(18,-27)

R(-15,3)\rightarrow R'(3(-15),3(3))=R'(-45,9)

The vertices of image are P'(9,-18), Q'(18,-27) and R'(-45,9).

Therefore, the correct option is C.

6 0
1 year ago
The area of John’s rectangular lawn and cement border is 1222 square feet. If the cement border is 2 feet wide, and the length o
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Step-by-step explanation:

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Read 2 more answers
A yogurt shop offers 6 different flavors of frozen yogurt and 12 different toppings. How many choices are possible for a single
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Answer:

#3) 72; #4) 40,320; #5) 90.

Step-by-step explanation:

#3) The number of possible choices are found by multiplying the choices of flavors and the choices of toppings:

6*12=72.

#4) The ordering of 8 cards is a permutation, given by 8!=40,320.

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7 0
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the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
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Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

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Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

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