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EastWind [94]
2 years ago
10

Select all polynomials that have (x-3)(x−3)left parenthesis, x, minus, 3, right parenthesis as a factor. Choose all answers that

apply: Choose all answers that apply: (Choice A) A A(x)=x^3-2x^2-4x+3A(x)=x 3 −2x 2 −4x+3A, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 2, x, squared, minus, 4, x, plus, 3 (Choice B) B B(x)=x^3+3x^2-2x-6B(x)=x 3 +3x 2 −2x−6B, left parenthesis, x, right parenthesis, equals, x, cubed, plus, 3, x, squared, minus, 2, x, minus, 6 (Choice C) C C(x)=x^4-2x^3-27C(x)=x 4 −2x 3 −27C, left parenthesis, x, right parenthesis, equals, x, start superscript, 4, end superscript, minus, 2, x, cubed, minus, 27 (Choice D) D D(x)=x^4-20x-21D(x)=x 4 −20x−21
Mathematics
1 answer:
iVinArrow [24]2 years ago
4 0

Answer:

  A, C, D

Step-by-step explanation:

One way to answer this question is to use synthetic division to find the remainder from division of the polynomial by (x-3). If the polynomial is written in Horner form, evaluating the polynomial for x=3 is substantially similar.

  A(x) = ((x -2)x -4)x +3

  A(3) = ((3 -2)3 -4)3 +3 = -3 +3 = 0 . . . . . has a factor of (x -3)

__

  B(x) = ((x +3)x -2)x -6

  B(3) = ((3 +3)3 -2)3 -6 = (16)3 -6 = 42 . . . (x -3) is not a factor

__

  C(x) = (x -2)x^3 -27

  C(3) = (3 -2)3^3 -27 = 0 . . . . . . . . . . . . . has a factor of (x -3)

__

  D(x) = (x^3 -20)x -21

  D(3) = (3^3 -20)3 -21 = (7)3 -21 = 0 . . . . has a factor of (x -3)

___

The polynomials of choice are A(x), C(x), and D(x).

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In a multiple choice exam, there are 5 questions and 4 choices for each question (a, b, c, d). Nancy has not studied for the exa
KonstantinChe [14]

Answer:

Part 1

a) 0.0791

b) 0.000977

c) 0.7627

Part 2

a) 0.049

b) 0.067

c) 0.864 or 0.136 (depending on what the question truly says)

d) 0.806

Step-by-step explanation:

Part 1

Since there are 4 choices per question, and only one correct answer per question.

The probability of getting a question right = (1/4) = 0.25

Probability of getting a question wrong = 1 - 0.25 = 0.75

a) Probability that the first question she gets right is the 5th question means she gets the first 4 questions wrong, and gets the last question.

0.75 × 0.75 × 0.75 × 0.75 × 0.25 = 0.0791

b) Probability that she gets all of the questions right

0.25 × 0.25 × 0.25 × 0.25 × 0.25 = 0.000977

c) Probability that she gets at least one question right = 1 - (probability that she doesn't get any question right) = 1 - (0.75⁵) = 1 - 0.2373 = 0.7627

Part 2

We use standard normal distribution for this

a) Area under (Z< -1.65) = P(z < -1.65) = 1 - P(z ≥ -1.65) = 1 - P(z ≤ 1.65) = 1 - 0.951 = 0.049

b) Area under (Z > 1.5) = P(z > 1.5) = 1 - P(z ≤ 1.5) = 1 - 0.933 = 0.067

c) P(z > -1.1) or P(z < -1.1)

P(z > - 1.1) = 1 - P(z ≤ -1.1) = 1 - 0.136 = 0.864

P(z < - 1.1) = 1 - P(z ≥ - 1.1) = 1 - P(z ≤ 1.1) = 1 - 0.864 = 0.136

d) |Z|>1.3 = P(-1.3 < z < 1.3) = P(z < 1.3) - P(z < -1.3)

P(z < 1.3) = 1 - P(z ≥ 1.3) = 1 - P(z ≤ -1.3) = 1 - 0.097 = 0.903

P(z < -1.3) = 1 - P(z ≥ -1.3) = 1 - P(z ≤ 1.3) = 1 - 0.903 = 0.097

P(z < 1.3) - P(z < -1.3) = 0.903 - 0.097 = 0.806

6 0
2 years ago
As concert goers enter a stadium, a security guard randomly inspects their backpacks for alcoholic beverages. Of 130 backpacks c
lisov135 [29]

Answer:

a. The population refers to targeted area under study which is all the backpacks of concertgoers

b. The sample refers to that part of the population inspected for study which is the number of backpacks checked in this case

c. P is the percentage or proportion of all backpacks of concertgoers that contained alcoholic beverages

e Using a confidence interval of 95%, I will.

This is because the true proportion lies between 7.3% and 18.9% and the data given in the question has an estimate of 13.1% which lies within the range of values

Step-by-step explanation:

PLEASE CHECK ATTACHMENT FOR EXPLANATION AND STEP BY STEP SOLUTION

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Which statement is true regarding the graphed functions?
katen-ka-za [31]

let's analyze each case to determine the solution

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For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 1) is false

<u>case 2) </u>f(0) = 4 and g(–2) = 4

For x=0-----> find the value of f(0) in the graph-----> f(0)=4

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 2) is false

<u>case 3) </u>f(2) = 0 and g(–2) = 0

For x=2-----> find the value of f(2) in the graph-----> f(2)=0

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 3) is true

<u>case 4) </u>f(–2) = 0 and g(–2) = 0

For x=-2-----> find the value of f(-2) in the graph-----> f(-2) is greater than 12

For x=-2-----> find the value of g(-2) in the graph-----> g(-2)=0

therefore

the statement of the case 4) is false

therefore

<u>the answer is</u>

f(2) = 0 and g(–2) = 0-------> this statement is true





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