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zubka84 [21]
2 years ago
14

Line l has a slope of 2. The line through which of the following pair of points is perpendicular to l?

Mathematics
2 answers:
djverab [1.8K]2 years ago
8 0

Answer:

D

Step-by-step explanation:

If two lines are perpendicular, the products of their slopes will be -1. Therefore, we're looking for a line with slope of -1/2. Let's check each answer:

A: 5 - 3 / (-2 - 3) = 2 / -5    

B: 6 - 5 / 6 - 5 = 1

C: 5 - 3 / 4 - 3 = 2

D: 4 - 3 / 3 - 5 = -1/2

The answer is D.

s344n2d4d5 [400]2 years ago
6 0

Answer:

A. (-2,5),(3,3)

Step-by-step explanation:

Look at the image below.

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A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0
1 year ago
World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of
Sunny_sXe [5.5K]

Answer:

a) W(t) = 371(1.168)^{t}

b) Wind capacity will pass 600 gigawatts during the year 2018

Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

(1.168)^{t} = 1.61725

We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

7 0
2 years ago
The two prisms below are similar. What is the value of x?
Alex73 [517]

Answer:

<em>The </em><em>val</em><em>ue</em><em> of</em><em> </em><em>x</em><em> </em><em>is</em><em> </em><em>D</em><em>.</em><em> </em><em>3</em><em>0</em>

Step-by-step explanation:

hope it works out!!!!

3 0
2 years ago
Read 2 more answers
A quality control manager at an auto plant measures the paint thickness on newly painted cars. A certain part that they paint ha
Scorpion4ik [409]

Answer:

78.88% probability that the mean thickness in the sample of 100 points is within 0.1 mm of the target value

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 2, \sigma = 0.8, n = 100, s = \frac{0.8}{\sqrt{100}} = 0.08

What is the probability that the mean thickness in the sample of 100 points is within 0.1 mm of the target value?

This is the pvalue of Z when X = 2 + 0.1 = 2.1 subtracted by the pvalue of Z when X = 2 - 0.1 = 1.9. So

X = 2.1

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{2.1 - 2}{0.08}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 1.9

Z = \frac{X - \mu}{s}

Z = \frac{1.9 - 2}{0.08}

Z = -1.25

Z = -1.25 has a pvalue of 0.1056

0.8944 - 0.1056 = 0.7888

78.88% probability that the mean thickness in the sample of 100 points is within 0.1 mm of the target value

8 0
2 years ago
Ms. Corley wants to take her class on a trip to either the nature center or the zoo the nature center charges $4 per student plu
lianna [129]
X- class members
y-total cost of a trip
The nature center: y=4$*x+95$
The zoo: y=9$*x+75$
4x+95=9x+75⇒5x=20⇒x=20/5
x=4, y=111
<span>If Ms. Corley has 22 students in her class, cost for nature center would be 4$*22+95$=183$ and for the zoo 9$*22+75$=273$.
The zoo would cost less.
</span>
3 0
1 year ago
Read 2 more answers
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