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Umnica [9.8K]
2 years ago
14

By selling goods for $168, a profit of 12% was made by a merchant . How much did the goods cost him ?

Mathematics
1 answer:
stellarik [79]2 years ago
5 0

Answer:

$147.84

Step-by-step explanation:

168 * 0.12 = 20.16

168-20.16 = 147.84

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Henry bought 2 kilograms of chicken for a family dinner. After dinner, only 61.5 grams were left. How much chicken was eaten, in
DedPeter [7]

Answer:

1.99385kg of chicken was eaten.

Step-by-step explanation:

We first need to know how many grams were left in kilograms, so we can find the difference.

Unit conversion: 6.15g x 1kg/1000g = 0.00615kg

Eaten amount of chicken: 2kg - 0.00615kg = 1.99385kg

Hungry family, I suppose...

3 0
2 years ago
A man is 6 feet 2 inches tall. To find the height of a tree, the shadow of the man and the shadow of the tree were measured. The
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3 0
2 years ago
The height of a baseball thrown from the catcher to first base is modeled by the function h(t) = –0.09t2 + 0.72t + 6, where h is
Black_prince [1.1K]

The height of a baseball thrown from the catcher to first base is modeled by the function h(t) = -0.09t^2 + 0.72t + 6, where h is the height of the ball measured in feet and t is the time since being thrown, measured in seconds

To find out height of the ball at 10 seconds, we plug in 10 for t

h(t) = -0.09t^2 + 0.72t + 6

h(10) = -0.09(10)^2 + 0.72(10) + 6

h(10)=4.2 feet

the height of the ball at 10 seconds= 4.2 feet

3 0
2 years ago
The average annual amount American households spend for daily transportation is $6312 (Money, August 2001). Assume that the amou
lions [1.4K]

Answer:

(a) The standard deviation of the amount spent is $3229.18.

(b) The probability that a household spends between $4000 and $6000 is 0.2283.

(c) The range of spending for 3% of households with the highest daily transportation cost is $12382.86 or more.

Step-by-step explanation:

We are given that the average annual amount American households spend on daily transportation is $6312 (Money, August 2001). Assume that the amount spent is normally distributed.

(a) It is stated that 5% of American households spend less than $1000 for daily transportation.

Let X = <u><em>the amount spent on daily transportation</em></u>

The z-score probability distribution for the normal distribution is given by;

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = average annual amount American households spend on daily transportation = $6,312

           \sigma = standard deviation

Now, 5% of American households spend less than $1000 on daily transportation means that;

                      P(X < $1,000) = 0.05

                      P( \frac{X-\mu}{\sigma} < \frac{\$1000-\$6312}{\sigma} ) = 0.05

                      P(Z < \frac{\$1000-\$6312}{\sigma} ) = 0.05

In the z-table, the critical value of z which represents the area of below 5% is given as -1.645, this means;

                           \frac{\$1000-\$6312}{\sigma}=-1.645                

                            \sigma=\frac{-\$5312}{-1.645}  = 3229.18

So, the standard deviation of the amount spent is $3229.18.

(b) The probability that a household spends between $4000 and $6000 is given by = P($4000 < X < $6000)

      P($4000 < X < $6000) = P(X < $6000) - P(X \leq $4000)

 P(X < $6000) = P( \frac{X-\mu}{\sigma} < \frac{\$6000-\$6312}{\$3229.18} ) = P(Z < -0.09) = 1 - P(Z \leq 0.09)

                                                            = 1 - 0.5359 = 0.4641

 P(X \leq $4000) = P( \frac{X-\mu}{\sigma} \leq \frac{\$4000-\$6312}{\$3229.18} ) = P(Z \leq -0.72) = 1 - P(Z < 0.72)

                                                            = 1 - 0.7642 = 0.2358  

Therefore, P($4000 < X < $6000) = 0.4641 - 0.2358 = 0.2283.

(c) The range of spending for 3% of households with the highest daily transportation cost is given by;

                    P(X > x) = 0.03   {where x is the required range}

                    P( \frac{X-\mu}{\sigma} > \frac{x-\$6312}{3229.18} ) = 0.03

                    P(Z > \frac{x-\$6312}{3229.18} ) = 0.03

In the z-table, the critical value of z which represents the area of top 3% is given as 1.88, this means;

                           \frac{x-\$6312}{3229.18}=1.88                

                         {x-\$6312}=1.88\times 3229.18  

                          x = $6312 + 6070.86 = $12382.86

So, the range of spending for 3% of households with the highest daily transportation cost is $12382.86 or more.

8 0
2 years ago
The price of a recipe-book was reduced from $24.50 to$17.95. If p represents the percent decrease in price of the book, which pr
LuckyWell [14K]

Answer:

The required proportion is \frac{p}{100}=\frac{24.50-17.95}{24.50}.

Step-by-step explanation:

Consider the provided information.

The price of a recipe-book was reduced from $24.50 to$17.95.

The original price is 24.50

Reduced price is 17.95.

Let p represents the percent decrease in price of the book.

\text{Percent decrease}=\frac{\text{Original price-Reduced price}}{\text{Original price}}\times 100

Now substitute the respective values in the above formula.

p=\frac{24.50-17.95}{24.50}\times 100

\frac{p}{100}=\frac{24.50-17.95}{24.50}

Hence, the required proportion is \frac{p}{100}=\frac{24.50-17.95}{24.50}.

4 0
2 years ago
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