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solmaris [256]
2 years ago
5

A claim is made that expression 1 and expression 2 are equivalent. A student is asked to provide proof that the claim is true.

Mathematics
2 answers:
Nezavi [6.7K]2 years ago
7 0

Answer:

The answer is B and A

Step-by-step explanation:

finlep [7]2 years ago
5 0

Answer:

The answer is B

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Kari is flying a kite. She releases 50 feet of string. What is the approximate difference in the height of the kite when the str
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Sinα=h/L  where h=height, L=string length...

h=Lsinα  so

h(25°)=50sin25≈21.1ft

h(45°)=50sin45≈35.4ft
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2 years ago
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A spherical scoop of ice cream is placed on top of a hollow ice cream cone. the scoop and cone have the same radius. the ice cre
noname [10]
The figure shown below illustrates the problem.

The volume of the empty cone is
V₁ = (1/3) π r²h

The volume of the sphere is
V₂ = (4/3) π r³

Because the melted ice cream completely fills the cone, therefore
V₁ = V₂
(1/3) π r² h = (4/3) π r³
Divide each side by (1/3) π r².
h = 4r

Answer:
The height of the cone is 4 times greater than the radius f the cone.

5 0
2 years ago
A carpenter is framing an opening in a wall to hang a rectangular door. Which properties must the door frame have to ensure that
tigry1 [53]
A) The top and bottom are parallel.B)The top and right side form a right angle.D)The left side and right side are parallel.E)The left side and bottom form a right angle.
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The data set below represents the ages of 36 executives. find the percentile that corresponds to an age of 4141 years old. 2828
solong [7]

Answer:

37th percentile.

Step-by-step explanation:

We have been given a data set that represents the ages of 36 executives. We are asked to find the percentile that corresponds to an age of 41 years.

28, 29, 29, 32, 32, 33, 34, 34, 34, 34, 37, 37, 38, 41, 41, 42, 45, 45, 47, 47, 47, 48, 50, 51, 53, 56, 56, 56, 61, 61, 62, 63, 64, 64, 65, 66.

Let us count the number of data points below and at 41.

We can see that the number of data points at and below 41 is 13.

We will use percentile formula to solve our given problem.

\text{Percentile rank of x}=\frac{\text{Number of values below x}}{\text{Total number of data points}}\times 100

\text{Percentile rank of 41}=\frac{13}{36}\times 100

\text{Percentile rank of 41}=0.361111\times 100

\text{Percentile rank of 41}=36.11\approx 37

Therefore, the percentile rank that corresponds to age of 41 years old is 37th percentile.  

8 0
2 years ago
You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
2 years ago
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