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AleksandrR [38]
2 years ago
11

David opened a coffee shop and sold 60 mochas the first day at $2 per cup. He wants to increase the price per cup to increase hi

s revenue. He found out that for every $0.25 increase, x, in the price per cup, the number of cups he sold decreased by 2 per day.
How can David find the equation which represents his daily revenue, in dollars, from mocha sales when the price is increased x times?

A. Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 19x + 120.

B. Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 11x + 120.

C. Multiply (60 − 0.25x) and (2 + 2x) to create the equation y = -0.5x2 + 119.5x + 120.

D. Multiply (60 − 0.25x) and (2 + 2x) to create the equation y = -0.5x2 + 120.5x + 120.
Mathematics
2 answers:
viktelen [127]2 years ago
7 0

Answer:

B. Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 11x + 120

Step-by-step explanation:

x is the number of price increases of 0.25 each, so (2 + 0.25x) will be the price after x increases.

2 cups remain unsold for every increase in price, so for x increases, 2x cups remain unsold. Then the number sold is (60 -2x).

Revenue is the product of price and quantity sold, so is ...

... revenue = (60 -2x)(2 +0.25x) . . . . . . matches selections A or B

The product of these binomials is ...

... 60·2 +60·0.25x -2x·2 -2x·0.25x

... = -0.5x² +11x +120 . . . . . . . . . . . . . . . . matches selection B

Alika [10]2 years ago
4 0

He wants to increase the price per cup to increase his revenue. He found out that for every $0.25 increase, x, in the price per cup,

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Copy and complete each table.
LUCKY_DIMON [66]

Answer:

5th term of sequence = -18

nth term of the sequence = -5n + 7

Step-by-step explanation:

Difference between successive and previous term of the output,

T_{2}-T_{1} = -3 - 2

           = -5

Similarly, T_{3}-T_{2}=-8-(-3)

                            = -5

There is a common difference 'd' = (-5)

Therefore, the sequence formed will be an arithmetic sequence.

First term of the sequence 'a' = 2

Explicit formula of an arithmetic sequence, T_{n} = a + (n - 1)d  [n = input value]

T_{n} = 2 + (n - 1)(-5)

    = 2 - 5n + 5

    = -5n + 7

5th term of this sequence,

T_{5}=2+(5-1)(-5)

    = 2 - 20

    = -18

Therefore, 5th term of sequence = -18

                  nth term of the sequence = -5n + 7

3 0
1 year ago
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
1 year ago
If f(x) = 53 - 2x, then f(-3) =
zheka24 [161]
Substitute -3 for x in the expression

f(x)= 53 - 2x

f(-3)= 53 - 2(-3)
multiply -2 * -3

f(-3)= 53 + 6
add

f(-3)= 59


ANSWER: f(-3)= 59

Hope this helps! :)
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1 year ago
A recipe for uncle Frank's homemade hush puppies call four 1/8 teaspoon of cyan pepper the recipe calls for six times as much as
Vinil7 [7]
I believe the answer is 3 teaspoons
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2 years ago
PLEASE HELP! Robin bought a four-scoop ice cream cone having a scoop each of vanilla, chocolate, strawberry, and cherry. In how
soldi70 [24.7K]
There are 3 choices for the bottom scoop. Then there are only 3 choices for the scoop above that (since one flavor has already been used), then 2 choices for the next scoop, and 1 choice for the final scoop. This gives a total of 18 <span>possible cones.




Hope this helps.
</span>
4 0
2 years ago
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