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AleksandrR [38]
1 year ago
11

David opened a coffee shop and sold 60 mochas the first day at $2 per cup. He wants to increase the price per cup to increase hi

s revenue. He found out that for every $0.25 increase, x, in the price per cup, the number of cups he sold decreased by 2 per day.
How can David find the equation which represents his daily revenue, in dollars, from mocha sales when the price is increased x times?

A. Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 19x + 120.

B. Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 11x + 120.

C. Multiply (60 − 0.25x) and (2 + 2x) to create the equation y = -0.5x2 + 119.5x + 120.

D. Multiply (60 − 0.25x) and (2 + 2x) to create the equation y = -0.5x2 + 120.5x + 120.
Mathematics
2 answers:
viktelen [127]1 year ago
7 0

Answer:

B. Multiply (60 − 2x) and (2 + 0.25x) to create the equation y = -0.5x2 + 11x + 120

Step-by-step explanation:

x is the number of price increases of 0.25 each, so (2 + 0.25x) will be the price after x increases.

2 cups remain unsold for every increase in price, so for x increases, 2x cups remain unsold. Then the number sold is (60 -2x).

Revenue is the product of price and quantity sold, so is ...

... revenue = (60 -2x)(2 +0.25x) . . . . . . matches selections A or B

The product of these binomials is ...

... 60·2 +60·0.25x -2x·2 -2x·0.25x

... = -0.5x² +11x +120 . . . . . . . . . . . . . . . . matches selection B

Alika [10]1 year ago
4 0

He wants to increase the price per cup to increase his revenue. He found out that for every $0.25 increase, x, in the price per cup,

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Using the normal distribution and the central limit theorem, it is found that  there is a 0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

----------------------------------

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

----------------------------------

  • Mean of 700g means that \mu = 700
  • Standard deviation of 21g means that \sigma = 21
  • Sample of 64, thus n = 64
  • <u>For the sampling distribution of the sample mean</u>, the standard deviation is of s = \frac{21}{\sqrt{64}} = \frac{21}{8} = 2.625

The probability of finding a sample mean mass of 695g or below is the p-value of Z when X = 695, thus:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{695 - 700}{2.625}

Z = -1.905

Z = -1.905 has a p-value of 0.0284.

0.0284 = 2.84% probability of finding a sample mean mass of 695g or below.

A similar problem is given at brainly.com/question/22934264

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