Answer:
701 revolutions
Step-by-step explanation:
Given: Length= 2.5 m
Radius= 1.5 m
Area covered by roller= 16500 m²
Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.
Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.
Formula; Lateral surface area of cylinder= 
Considering, π= 3.14
⇒ lateral surface area of cylinder= 
⇒ lateral surface area of cylinder= 
∴ Area covered by cylindrical roller in one revolution is 23.55 m²
Next finding total number of revolution to cover 16500 m² area.
Total number of revolution= 
Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.
Answer:
Step-by-step explanation:
xy = 2y + xy = 0
Hence, 2y + xy = 0 ---------(1)
Differentiating equation (1) n times by Leibnitz theorem, gives:
2y(n) + xy(n) + ny(n - 1) = 0
Let x = 0: 2y(n) + ny(n - 1) = 0
2y(n) = -ny(n - 1)
∴ y(n) = -ny(n - 1)/2 for n ≥ 1
For n = 1: y = 0
For n = 2: y(1) = -y
For n = 3: -3y(2)/2
For n = 4: -2y(3)
8/15 or 11/15 would b the probabiltity of those